JNU Entrance /Quantitative Aptitude

Average

Arithmetic · free study notes · Updated

📚 Quantitative Aptitude – Average

Average (Mean) is the sum of a set of numbers divided by the count of numbers.
It gives a central value that represents the whole data set.


1. Simple Explanation

  • Arithmetic Mean (Unweighted Average)
    [ \text{Mean} = \frac{\sum \text{values}}{\text{number of values}} ]

  • Weighted Average – each value has a weight (importance)
    [ \text{Weighted Mean} = \frac{\sum (\text{value} \times \text{weight})}{\sum \text{weights}} ]

  • Harmonic Mean – used when averaging rates or ratios
    [ \text{Harmonic Mean} = \frac{n}{\sum \frac{1}{\text{value}}} ]

Why it matters: Averages simplify data, help compare groups, and are used in many JEE‑type problems (average speeds, scores, weights, etc.).


2. Key Points

Concept Formula When to Use
Arithmetic Mean (\displaystyle \bar{x} = \frac{\sum_{i=1}^{n} x_i}{n}) Equal weight, ordinary averages
Weighted Mean (\displaystyle \bar{x}w = \frac{\sum{i=1}^{n} w_i x_i}{\sum_{i=1}^{n} w_i}) Different importance (e.g., marks in subjects, speeds over distances)
Harmonic Mean (\displaystyle H = \frac{n}{\sum_{i=1}^{n} \frac{1}{x_i}}) Averaging rates (speed, density)
Median Middle value in an ordered set Robust against outliers
Mode Most frequent value Categorical data
Properties • Non‑negative if all numbers non‑negative.
• Mean ≤ Max, Mean ≥ Min.
• Adding a number changes the mean in a predictable way.
• Helps estimate totals or missing data.
• Useful in solving “average change” type problems.

3. Worked Example

Problem (Typical JNU Entrance style):

The average score of 5 students in a test is 70. Three of them score 65, 75, and 80. What did the remaining two students score?

Steps

  1. Let the unknown scores be (x) and (y).

  2. Set up the equation using the definition of average:

    [ \frac{65 + 75 + 80 + x + y}{5} = 70 ]

  3. Multiply both sides by 5:

    [ 65 + 75 + 80 + x + y = 350 ]

  4. Sum the known scores:

    [ 220 + x + y = 350 ]

  5. Isolate (x + y):

    [ x + y = 350 - 220 = 130 ]

  6. Interpretation:
    The sum of the remaining two scores must be 130.
    Any pair of numbers that sum to 130 works (e.g., 60 & 70, 65 & 65, etc.)
    (If the problem asks for “the possible scores”, you’d list possibilities or note that the information is insufficient for unique values.)


Another Example – Weighted Average (Average Speed)

Problem:

A train travels 60 km at 60 km/h and then 40 km at 80 km/h. Find the average speed for the whole journey.

  1. Use weighted mean with distance as weight:

    [ \bar{v} = \frac{60 \times 60 + 40 \times 80}{60 + 40} = \frac{3600 + 3200}{100} = \frac{6800}{100} = 68\ \text{km/h} ]

  2. Answer:
    The average speed is 68 km/h.


4. Quick Revision Summary

  • Arithmetic Mean = total ÷ count.
  • Weighted Mean = Σ(weight × value) ÷ Σ(weight).
  • Harmonic Mean = count ÷ Σ(1/value).
  • Adding a new value:
    [ \bar{x}{new} = \frac{n\bar{x}{old} + x_{\text{new}}}{n+1} ]
  • Removing a value:
    [ \bar{x}{new} = \frac{n\bar{x}{old} - x_{\text{removed}}}{n-1} ]
  • Average problems often involve:
    • Missing data estimation.
    • Rate problems (speed, density).
    • Comparing groups.
  • Tips for JNU Entrance:
    1. Read carefully – check if it's a weighted scenario.
    2. Set up an equation using the definition of average.
    3. Simplify arithmetic – use mental math for sums.
    4. Check units – especially in speed or rate problems.

Practice Idea:

  1. Find the average of 8 numbers if the average is 15 and the sum of 4 numbers is 50.
  2. A student scored 45, 55, 65, 75, and 85 in 5 subjects with weightages 1, 2, 3, 4, 5 respectively. Compute the weighted average.

Use these notes to master the concept of averages and tackle a wide variety of quantitative problems confidently!

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