📚 PTE Quantitative Aptitude – Number System
(Study Notes for Quick Revision)
1️⃣ Simple Explanation
A number system is a set of numbers and the rules for manipulating them. In the PTE exam we mainly deal with:
| System | Definition | Examples |
|---|---|---|
| Natural numbers | Counting numbers starting from 1. | 1, 2, 3, … |
| Whole numbers | Natural numbers + 0. | 0, 1, 2, … |
| Integers | Whole numbers + their negatives. | …‑3, ‑2, ‑1, 0, 1, 2, … |
| Rational numbers | Numbers that can be expressed as a fraction p/q where p, q are integers and q ≠ 0. |
½, 4, –3/7, 0.75 |
| Irrational numbers | Numbers that cannot be expressed as a ratio of integers (non‑terminating, non‑repeating decimal). | √2, π, e |
| Real numbers | All rational + irrational numbers. | 0, 1/3, √5 |
| Complex numbers | Numbers of the form a + bi where i² = –1. |
3 + 4i |
In PTE you’ll mostly need to identify which category a number belongs to and use simple properties (divisibility, parity, etc.) to solve problems.
2️⃣ Key Points & Rules
| Topic | Key Point | Quick Test |
|---|---|---|
| Parity | Even numbers are divisible by 2; odd numbers are not. | Write n ÷ 2. If remainder 0 → even. |
| Divisibility Tests | 2,3,4,5,6,7,8,9,10,11,12,13,15,20,25,30,36,40,50,60,70,100. | Remember the standard rules: |
| 2 | last digit even | |
| 3 | sum of digits divisible by 3 | |
| 4 | last two digits divisible by 4 | |
| 5 | last digit 0 or 5 | |
| 6 | divisible by both 2 & 3 | |
| 7 | Rule of 2×last digit (subtract 2×last digit from remaining number; repeat) | |
| 8 | last three digits divisible by 8 | |
| 9 | sum of digits divisible by 9 | |
| 10 | last digit 0 | |
| 11 | alternating sum of digits divisible by 11 | |
| 12 | divisible by both 3 & 4 | |
| 13 | Rule of 4×last digit (add 4×last digit to remaining number; repeat) | |
| 15 | divisible by both 3 & 5 | |
| 20 | last two digits 00,20,40,60,80 | |
| 25 | last two digits 00,25,50,75 | |
| 30 | divisible by both 3 & 10 | |
| 36 | divisible by both 4 & 9 | |
| 40 | last two digits 00,20,40,60,80 | |
| 50 | last digit 0 or 5 with second last digit 0 | |
| 60 | divisible by both 3 & 20 | |
| 70 | divisible by both 5 & 14 | |
| 100 | last two digits 00 | |
| Prime Numbers | A prime has exactly two distinct positive divisors: 1 and itself. | Test divisibility up to √n. |
| Composite Numbers | Not prime; has more than two divisors. | Any number >1 that isn’t prime. |
| Perfect Squares | n = k² (e.g., 1,4,9,16). |
Last digit 0,1,4,5,6,9; check square root. |
| Perfect Cubes | n = k³ (e.g., 1,8,27,64). |
Last digit 0,1,8,7,6,5,4,3,2,9; check cube root. |
| Factorial & Exponentials | n! = 1×2×…×n. Powers a^b. |
Use prime factorization for large numbers. |
| Number Representation | Integer part + fractional part. | Convert fractions to decimals or vice‑versa. |
| Decimal, Binary, Octal, Hexadecimal | Representations in base‑10, base‑2, base‑8, base‑16. | Understand conversion rules (e.g., 1010₂ = 10₁₀). |
3️⃣ Worked Example
Problem (PTE‑style)
Find how many integers between 100 and 200 (inclusive) are divisible by 12 but not by 9.
Step‑by‑Step Solution
-
Find multiples of 12 in the range.
- Smallest multiple of 12 ≥ 100:
[ \lceil 100/12 \rceil = 9 \Rightarrow 9 \times 12 = 108 ] - Largest multiple of 12 ≤ 200:
[ \lfloor 200/12 \rfloor = 16 \Rightarrow 16 \times 12 = 192 ] - Count =
16 – 9 + 1 = 8multiples: 108, 120, 132, 144, 156, 168, 180, 192.
- Smallest multiple of 12 ≥ 100:
-
Filter out multiples of 9.
- A number divisible by both 12 and 9 is divisible by
LCM(12,9) = 36. - Find multiples of 36 in the range:
[ \lceil 100/36 \rceil = 3 \Rightarrow 3 \times 36 = 108 ] [ \lfloor 200/
- A number divisible by both 12 and 9 is divisible by