MCAT Reasoning Ability – Coding‑Decoding
Coding‑decoding (also called “coding‑decoding” or “coding‑decoding–pairs”) is one of the four core question types in the Reasoning Ability (RA) section of the MCAT.
In a coding‑decoding set you are given a code key that maps each letter of the alphabet to a different word.
Your task is to use the key to translate a coded sentence into plain English (or vice‑versa).
1. Simple Explanation
- Code Key: 26 distinct words, each assigned to a letter A‑Z (order is random, but no two letters share the same word).
- Coded sentence: A string of words that correspond to letters.
- Goal: Convert the coded sentence back into a normal sentence (or, in some cases, translate a normal sentence into the coded language).
Think of it as a simple substitution cipher where each word is a stand‑in for a letter.
2. Key Points
| # | Point | Why it matters |
|---|---|---|
| 1 | Unique mapping | Each word maps to exactly one letter; no duplicates. |
| 2 | Word‑to‑letter, not letter‑to‑word | The key is word → letter; you never reverse it directly. |
| 3 | Context clues | The meaning of the coded sentence often hints at the decoded words (e.g., “the” → “the”). |
| 4 | Letter frequency | Common English letters (E, T, A, O, I, N, S, H, R) appear frequently. Use this to guess words. |
| 5 | Word length | The length of the coded word indicates the length of the decoded word. |
| 6 | Common words | Familiarity with high‑frequency English words (e.g., “and”, “that”, “with”) speeds decoding. |
| 7 | Process of elimination | Once a word is decoded, remove its letters from the pool; this narrows possibilities for other words. |
| 8 | Check consistency | After a tentative translation, verify that each letter appears the same number of times in the decoded sentence as in the key. |
| 9 | Time management | Allocate ~1–1.5 min per coding‑decoding pair; skip if you hit a wall and return later. |
| 10 | Practice | The more patterns you see, the faster you’ll spot common words and letter patterns. |
3. Worked Example
3.1 The Coding Key
| Letter | Word |
|---|---|
| A | apple |
| B | banana |
| C | coconut |
| D | dog |
| E | elephant |
| F | frog |
| G | grape |
| H | hat |
| I | ice |
| J | jelly |
| K | kite |
| L | lion |
| M | monkey |
| N | newt |
| O | orange |
| P | panda |
| Q | queen |
| R | rabbit |
| S | snake |
| T | tiger |
| U | umbrella |
| V | violin |
| W | whale |
| X | xylophone |
| Y | yarn |
| Z | zebra |
Note: The key is random; the example uses simple animal words for illustration.
3.2 The Coded Sentence
coconut banana grape banana apple banana
3.3 Decoding Steps
| Step | Action | Explanation |
|---|---|---|
| 1 | List the words | coconut, banana, grape, banana, apple, banana |
| 2 | Map to letters | coconut→C, banana→B, grape→G, apple→A |
| 3 | Translate | C B G B A B |
| 4 | Form a word | CBGAB? (doesn't look like an English word) |
| 5 | Check for common words | The pattern B B B suggests “and” or “but”? But we have 3 B’s. |
| 6 | Use word length | 6 words = 6‑letter sentence. |
| 7 | Try a plausible sentence | “C B G B A B” → “C B G B A B” – maybe “C”=I, “B”=n, “G”=t, “A”=e, then “I n t n e n” → “intnen” (no). |
| 8 | Re‑examine key | Did we mis‑associate? Maybe banana is not B but something else? But key says banana→B. |
| 9 | Consider common short words | 1‑letter words: “I” and “a”. We don’t have a 1‑letter word. |
| 10 | Look at frequency | B appears thrice → likely “and” or “but” (3 letters). |
| 11 | Try “and” | B = A? No, B is a word, not a letter. |
| 12 | Re‑think | Actually, each word in the coded sentence corresponds to a letter in the decoded sentence. So the decoded sentence is 6 letters long, not 6 words. |
| 13 | Thus we need a 6‑letter word | The pattern of letters: C B G B A B. |
| 14 | Try to find a 6‑letter word with that pattern | _ _ _ _ _ _. We know the 2nd and 4th and 6th letters are B, the 5th is A, the 1st is C, the 3rd is G. |
| 15 | Check possibilities | The only 6‑letter words with pattern _ B _ B _ B are rare. |
| 16 | Maybe we mis‑read | Wait, we might have mis‑chosen the key. Let's swap banana and grape: Suppose banana→G, grape→B. Then we get: coconut→C, banana→G, |