Tamil Nadu Forest Guard /Quantitative Aptitude

Ratio & proportion

Arithmetic · free study notes · Updated

Ratio & Proportion – Study Notes

Program: Tamil Nadu Forest Guard
Subject: Quantitative Aptitude


1. Simple Explanation

  • Ratio – A comparison of two numbers using “:”.
    [ \text{Example: } 3:2 ;\text{means}; \frac{3}{2};\text{or};\frac{3}{2} ]

  • Proportion – An equation stating that two ratios are equal.
    [ \frac{a}{b} = \frac{c}{d};;\Longleftrightarrow;; a \times d = b \times c ]

  • Direct Proportion – When one quantity increases, the other increases in the same way.
    [ y = kx \quad (k\text{ is a constant}) ]

  • Inverse Proportion – When one quantity increases, the other decreases in such a way that their product is constant.
    [ y = \frac{k}{x} ]


2. Key Points (Cheat‑Sheet)

Topic Formula / Rule How to Use
Basic Proportion (\displaystyle \frac{a}{b} = \frac{c}{d}) Cross‑multiply: (a \times d = b \times c)
Missing in Ratio (\displaystyle \frac{a}{b} = \frac{c}{x}) (x = \frac{b \times c}{a})
Direct Proportion (y = kx) Find (k) using known pair ((x_1,y_1)): (k = \frac{y_1}{x_1}).
Inverse Proportion (y = \frac{k}{x}) Find (k) using known pair ((x_1,y_1)): (k = x_1y_1).
Ratio Simplification (\frac{a:b}{c:d} \Longrightarrow \frac{a}{b} \times \frac{d}{c}) Reduce to simplest integers.
Changing Ratios If ratio changes by factor (m:n), multiply numerator & denominator by (m) and (n) respectively. (\displaystyle \frac{a}{b} \times \frac{m}{n})
Finding Unknowns Set up proportion with known and unknown terms. Use cross‑multiplication or algebraic manipulation.

3. Worked Example

Problem

The ratio of boys to girls in a school is 5 : 3.
If there are 200 students in total, how many boys and how many girls are there?

Step‑by‑Step Solution

  1. Express the ratio as a proportion.
    [ \frac{\text{boys}}{\text{girls}} = \frac{5}{3} ]

  2. Let number of boys = (5x), number of girls = (3x) (common factor (x)).
    Because the ratio 5:3 tells us that for every 5 boys there are 3 girls.

  3. Total students =
    [ 5x + 3x = 200 ;;\Longrightarrow;; 8x = 200 ]

  4. Solve for (x).
    [ x = \frac{200}{8} = 25 ]

  5. Find boys and girls.
    [ \text{Boys} = 5x = 5 \times 25 = 125 ] [ \text{Girls} = 3x = 3 \times 25 = 75 ]

Answer

Boys = 125, Girls = 75


4. Quick Revision Summary

  1. Ratio = (a:b) → (a) compared with (b).
  2. Proportion = (\frac{a}{b} = \frac{c}{d}) → Cross‑multiply: (ad = bc).
  3. Direct Proportion: (y = kx ;(k = \frac{y}{x})).
  4. Inverse Proportion: (y = \frac{k}{x} ;(k = xy)).
  5. Finding a missing term:
    • If (\frac{a}{b} = \frac{c}{x}), then (x = \frac{b,c}{a}).
    • If (\frac{a}{b} = \frac{x}{d}), then (x = \frac{a,d}{b}).
  6. Check your work
    • Simplify the ratio back to its simplest form.
    • Verify by multiplying cross‑terms.
  7. Practice tip: Convert every ratio problem into a proportion; cross‑multiply; solve for the unknown.

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