Average

Arithmetic · free study notes · Updated

Andhra Pradesh Police Sub‑Inspector (SI) – Quantitative Aptitude

Topic: Average


1. Simple Explanation

The average (often called the arithmetic mean) of a set of numbers is the single value that represents the central tendency of that set.
Formula
[ \text{Average} = \frac{\text{Sum of all values}}{\text{Number of values}} ]

It is the most common type of average used in exams, investigations, and everyday calculations.


2. Key Points

Concept What it Means Formula When to Use Common Pitfalls
Arithmetic Mean Sum of numbers ÷ count ( \bar{x} = \frac{\sum x_i}{n} ) General averages (marks, speeds, ages) Forgetting to divide by n or mis‑counting items
Weighted Mean Numbers have different importance (weights) ( \bar{x}_w = \frac{\sum w_i x_i}{\sum w_i} ) Exam marks with different marks, salary components Mixing up weights and values; forgetting to sum weights
Harmonic Mean Average of reciprocals (useful for rates) ( H = \frac{n}{\sum (1/x_i)} ) Average speed when distance is equal, rates of flow Using it for normal data; forgetting to take reciprocal
Geometric Mean Product of numbers raised to 1/n (for growth rates) ( G = (\prod x_i)^{1/n} ) Compound interest, population growth Applies only to positive numbers; often mis‑used for general data
Average of Two Numbers Quick shortcut ( \frac{a+b}{2} ) Quick checks Forgetting to divide by 2
Average Speed Distance ÷ time (if distance is same for each segment) ( v_{\text{avg}} = \frac{n\cdot d}{\sum t_i} ) Travel, traffic analysis Using simple mean of speeds instead of harmonic mean

3. Worked Examples

Example 1: Arithmetic Mean of Five Numbers

Problem: Find the average of 12, 18, 25, 30, and 45.
Solution

  1. Sum: (12+18+25+30+45 = 130)
  2. Count: (n = 5)
  3. Average: (\displaystyle \frac{130}{5} = 26)
    Answer: 26

Example 2: Weighted Average

Problem: A candidate’s marks are 70 (30% weight), 85 (40% weight), and 90 (30% weight). What is the weighted average?
Solution

  1. Multiply each mark by its weight:
    • (70 \times 0.30 = 21)
    • (85 \times 0.40 = 34)
    • (90 \times 0.30 = 27)
  2. Sum of weighted marks: (21+34+27 = 82)
  3. Sum of weights: (0.30+0.40+0.30 = 1)
  4. Weighted mean: (\displaystyle \frac{82}{1} = 82)
    Answer: 82

Example 3: Average Speed (Harmonic Mean)

Problem: A vehicle travels 120 km at 60 km/h, then 120 km at 80 km/h. Find the average speed for the whole journey.
Solution

  1. Total distance: (120+120 = 240) km
  2. Time for each segment:
    • (t_1 = \frac{120}{60} = 2) h
    • (t_2 = \frac{120}{80} = 1.5) h
  3. Total time: (2 + 1.5 = 3.5) h
  4. Average speed: (\displaystyle \frac{240}{3.5} = 68.57) km/h (≈ 69 km/h)
    Answer: ~69 km/h

(Notice the use of harmonic mean because the distance is the same for each leg.)


4. Quick Revision Summary

Type Formula Usage Notes
Arithmetic Mean ( \bar{x} = \dfrac{\sum x_i}{n} ) General averages Always divide by n
Weighted Mean ( \bar{x}_w = \dfrac{\sum w_i x_i}{\sum w_i} ) Marks, salary, components Sum of weights must equal 1 or you must divide by ( \sum w_i )
Harmonic Mean ( H = \dfrac{n}{\sum

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