Punjab Police Constable /Quantitative Aptitude

Percentages

Arithmetic · free study notes · Updated

📌 Percentages – Quick Study Guide

Program: Punjab Police Constable
Subject: Quantitative Aptitude
Topic: Percentages


1️⃣ Simple Explanation

Percentage = part of a whole expressed in hundredths
1% = 1 part out of 100 parts.

When you have a number X and you want p% of X, you multiply X × p ÷ 100.
When you know the part P and the whole H, the percentage is (P ÷ H) × 100.


2️⃣ Key Points

Concept What to remember Quick check
Percent vs. Fraction 1% = 1/100. 25% = 25/100 = 1/4
Conversion % → decimal → multiply by 100. 12.5% → 0.125
Finding percentage of a number value = number × (percentage ÷ 100) 30% of 200 = 200 × 0.30 = 60
Finding number from its percentage number = value ÷ (percentage ÷ 100) 60 is 30% of what? → 60 ÷ 0.30 = 200
Percentage change change = (new – old) ÷ old × 100 80 → 100: (20 ÷ 80) × 100 = 25% ↑
Percentage increase/decrease Add/subtract percent of the base. 100 + 20% = 100 + (20/100 × 100) = 120
Profit / Loss Profit% = (Profit ÷ Cost Price) × 100 Loss% = (Loss ÷ Cost Price) × 100
Discount Discount% = (Discount ÷ Original Price) × 100 Sale Price = Original Price – Discount
Markup Markup% = (Markup ÷ Cost Price) × 100 Selling Price = Cost Price + Markup
Real‑World Always keep units consistent (₹, km, kg, etc.) Check if “percent of” refers to a whole or a part

3️⃣ Essential Formulas

Scenario Formula Example
Percent of a number P = N × (p ÷ 100) 25% of 80 → 80 × 0.25 = 20
Number from its percent N = P ÷ (p ÷ 100) 20 is 25% of what? → 20 ÷ 0.25 = 80
Percentage change Δ% = ((New – Old) ÷ Old) × 100 75 → 90: ((90‑75)/75)×100 = 20% ↑
Profit% Profit% = (Profit ÷ Cost Price) × 100 Cost = 200, Profit = 50 → 25%
Loss% Loss% = (Loss ÷ Cost Price) × 100 Cost = 200, Loss = 30 → 15%
Discount% Discount% = (Discount ÷ Original Price) × 100 Original = 500, Discount = 80 → 16%
Markup% Markup% = (Markup ÷ Cost Price) × 100 Cost = 120, Markup = 30 → 25%
Effective rate after successive changes Final = Base × (1 ± r1/100) × (1 ± r2/100)… 100 → +10% → -20% → 100×1.10×0.80 = 88

4️⃣ Worked Example (Full Problem)

Problem:
A shopkeeper bought a batch of 50 identical items for ₹6,000. He sold 30 items for ₹200 each. The remaining 20 items were sold later at a 10% profit on the cost price.
What is the overall profit percentage?

Solution Steps

  1. Cost Price (CP) of all items
    [ CP = ₹6,000 ]

  2. Selling Price (SP) of first 30 items
    [ SP_1 = 30 \times 200 = ₹6,000 ]

  3. Cost per item
    [ \text{Cost per item} = \frac{6000}{50} = ₹120 ]

  4. Selling price of remaining 20 items at 10% profit

    • Profit on one item = (120 \times 0.10 = ₹12)
    • SP per item = (120 + 12 = ₹132)
    • Total SP for 20 items = (20 \times 132 = ₹2,640)
  5. Total Selling Price
    [ SP_{\text{total}} = 6000 + 2640 = ₹9,640 ]

  6. Total Profit
    [ \text{Profit} = SP_{\text{total}} - CP = 9640 - 6000 = ₹3,640 ]

  7. Overall Profit %
    [ \text{Profit%} = \frac{3640}{6000} \times 100 \approx 60.67% ]

Answer: The shopkeeper’s overall profit is ≈ 60.7 %.


5️⃣ Quick Revision Summary

Topic Formula Quick Tip
Percent of a number P = N × p/100 Use 0.01 × p to convert percent to decimal.
Number from its percent N = P × 100/p Multiply by 100 first, then divide.
Percentage change Δ% = ((New – Old)/Old) × 100 Positive = increase, negative = decrease

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