Tripura Police Sub-Inspector (SI) /Quantitative Aptitude

Time & work

Commercial Maths · free study notes

Time & Work – Quantitative Aptitude (SI – Tripura Police Sub‑Inspector)

Exam Focus – IIT‑JEE / Competitive Exams
Topic – Time & Work
Target – Master the rate‑time‑work relationship, derive formulas from first principles, and solve problems that involve multiple workers, changes in workforce, and partial work.


1. Core Concepts & Definitions

Symbol Meaning Units
(W) Total work (job) units of work (e.g., “tasks” or “jobs”)
(r_i) Work‑rate of worker (i) units of work per day
(t_i) Time spent by worker (i) days
(T) Total time for a job days
(n) Number of workers dimensionless

Key Idea – Work is additive: If two workers work simultaneously, the combined rate is the sum of their individual rates.


2. Fundamental Work‑Rate Model

2.1 Work Done by a Single Worker

[ \boxed{W_i = r_i \times t_i} ]

Derivation – Work is rate × time.

2.2 Combined Rate of (n) Workers

[ \boxed{r_{\text{total}} = \sum_{i=1}^{n} r_i} ]

Proof – If each worker contributes (r_i) units/day, the total per day is the sum.

2.3 Time Required for a Job

[ \boxed{T = \frac{W}{r_{\text{total}}}} ]

Proof – Rearrange (W = r_{\text{total}} \times T).


3. Common Problem Structures

Problem Type Typical Question Typical Approach
Single worker A worker completes a job in 10 days. (r = W/10).
Multiple workers together 5 workers finish a job in 12 days. (T = 12), (n = 5). Find (W) or (r_{\text{total}}).
Workers with different rates A and B finish a job in 8 and 12 days respectively. (r_A = W/8), (r_B = W/12).
Partial work A worker works 4 days, then leaves. Compute work done before leaving, subtract from (W).
Work replacement One worker leaves after 2 days, another joins. Compute work done by each period.
Proportion of work A does 1/3 of job; B does 1/4. Translate fractions to rates.
Non‑linear relation Work done is inversely proportional to time. (r \propto 1/T).

4. Deriving Key Formulas (From First Principles)

4.1 Work Done by Two Workers

Let worker A do the job in (T_A) days, B in (T_B) days.

  • Rate of A: (r_A = \frac{W}{T_A})
  • Rate of B: (r_B = \frac{W}{T_B})

Combined rate: (r_A + r_B = \frac{W}{T_A} + \frac{W}{T_B}).

Time to finish together (T):

[ T = \frac{W}{r_A + r_B} = \frac{W}{\frac{W}{T_A} + \frac{W}{T_B}} = \frac{1}{\frac{1}{T_A} + \frac{1}{T_B}} = \frac{T_A T_B}{T_A + T_B} ]

Important Result – When two workers work together, the reciprocal of time is the sum of the reciprocals of individual times.

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