Ratio & Proportion – Sikkim PSC Quantitative Aptitude
Quick note – Ratio & Proportion is a core topic in Sikkim PSC. It is used to solve problems about parts of a whole, rate problems, age problems, mixing problems, and distance/time type questions. Mastering the basic rules and formulas will help you score high.
1. Simple Explanation
| Concept | What it means | Formula / Rule |
|---|---|---|
| Ratio | Comparison of two (or more) numbers. | a : b or a/b |
| Proportion | Two ratios are equal. | a : b = c : d ⇔ a/b = c/d |
| Direct Proportion | If one variable increases, another increases in the same proportion. | y = kx |
| Inverse Proportion | If one variable increases, another decreases in the same proportion. | y = k/x |
| Compound Ratio | More than two numbers in a ratio. | a : b : c |
| Part of a Whole | Find a part when the ratio of parts to the whole is known. | Part = (ratio / sum of ratios) × Total |
| Cross‑Multiplication | Method to solve proportions. | a × d = b × c |
2. Key Points (Bullet‑List)
- Always write ratios in simplest form (e.g.,
6 : 8→3 : 4). - If given a proportion
a : b = c : d, you can:- Solve for an unknown by cross‑multiplication:
a × d = b × c. - Find a missing part of a whole:
c = (b/(a+b)) × Total.
- Solve for an unknown by cross‑multiplication:
- Compound ratio – sum the individual parts to get the total parts.
- Example:
2 : 3 : 5→ total parts =2+3+5 = 10.
- Example:
- Part of a whole:
- If the parts are
x : y : zand the whole isT, then:Part_x = (x/(x+y+z)) × TPart_y = (y/(x+y+z)) × TPart_z = (z/(x+y+z)) × T
- If the parts are
- Rate problems – Treat rate as a ratio of two quantities.
- For example, “5 apples cost ₹25” → rate =
₹5 per apple→12 apples = 12×5 = ₹60.
- For example, “5 apples cost ₹25” → rate =
- Age problems – If age ratio is
p : qand one age is known, solve:Age_other = (q/p) × Age_known.
- Proportion in a line – If a line is divided in a ratio, find the length of a segment by applying the ratio to the whole length.
- Mixing / combining – When mixing two substances, use ratios of amounts to find the resulting mixture.
3. Worked Example
Problem (Sikkim PSC style)
Two numbers are in the ratio 3 : 5.
The sum of the numbers is 64.
Find the two numbers.
Step‑by‑Step Solution
-
Express the numbers in terms of a common variable
Let the two numbers be3xand5x(because the ratio is 3:5). -
Use the given sum
3x + 5x = 64
→8x = 64 -
Solve for
x
x = 64 ÷ 8 = 8 -
Find the numbers
- First number =
3x = 3 × 8 = 24 - Second number =
5x = 5 × 8 = 40
- First number =
-
Check
- Sum =
24 + 40 = 64✔️ - Ratio =
24 : 40 = 3 : 5✔️
- Sum =
Answer: The numbers are 24 and 40.
4. Quick Revision Summary
| Topic | What to remember |
|---|---|
| Ratio | a : b or a/b; simplify first |
| Proportion | a/b = c/d; cross‑multiply a×d = b×c |
| Compound ratio | Sum all parts to get total parts |
| Part of a whole | Part = (ratio / sum of ratios) × Total |
| Rate problems | Treat rate as value/quantity; apply directly |
| Age & distance | Use ratio age1 : age2 → age2 = (ratio2/ratio1) × age1 |
| Mixing | Combine proportions of each component |
Tip: Always write a clear equation first and keep track of units (₹, km, years, etc.) – this helps avoid mistakes in the final answer.
Happy studying! 🚀