ANM Admission /Physics

Fluids

Mechanics & Properties of Matter · free study notes · Updated

Fluids – Study Notes for ANM Admission (Physics)

Why you need this?
Fluids are everywhere – water, blood, air, and the many liquids we use in medicine. Understanding how they behave helps you interpret clinical situations (e.g., blood pressure, fluid balance, ventilation).


1. Simple Explanation

  • Fluid: A substance that can flow (liquids and gases).
  • Pressure: Force exerted perpendicular to a surface per unit area.
  • Density (ρ): Mass per unit volume.
  • Buoyancy: Upward force on an object immersed in a fluid, equal to the weight of the fluid displaced.
  • Viscosity: Internal resistance to flow – “thickness” of a fluid.
  • Flow rate (Q): Volume of fluid that passes through a cross‑section per unit time.

2. Key Points

Concept What It Means Formula Practical Example
Pressure Force per area (P = \frac{F}{A}) Blood pressure (= \frac{Force;on;arterial;wall}{Cross;sectional;area})
Hydrostatic Pressure Pressure due to fluid column (P = \rho g h) Pressure at 1 m depth in water
Pascal’s Law Pressure applied to an enclosed fluid is transmitted undiminished (P_1 = P_2) Hydraulic lift
Archimedes’ Principle Buoyant force equals weight of displaced fluid (F_b = \rho_{\text{fluid}};V_{\text{displaced}};g) Balloon floats in air
Density (\rho = \frac{m}{V}) – Blood density ≈ 1.06 g cm⁻³
Viscosity Resistance to flow (\eta) (dynamic) Blood viscosity higher in disease
Continuity Equation (A_1v_1 = A_2v_2) – Narrowing of a tube increases velocity
Bernoulli’s Equation Energy conservation in fluid flow (P + \frac{1}{2}\rho v^2 + \rho gh = \text{constant}) Venturi tube measurement

3. Worked Example (Hydrostatic Pressure)

Problem:
What is the hydrostatic pressure at a depth of 2 m in freshwater?
(Assume (ρ_{\text{water}} = 1000\ \text{kg m}^{-3}), (g = 9.81\ \text{m s}^{-2}))

Solution:

  1. Identify the formula:
    [ P = ρ g h ]
  2. Plug in the numbers:
    [ P = (1000\ \text{kg m}^{-3})(9.81\ \text{m s}^{-2})(2\ \text{m})
    ]
  3. Calculate:
    [ P = 19,620\ \text{Pa} \quad(\text{or } 19.6\ \text{kPa}) ]

Interpretation:
The pressure 2 m below the surface of still water is about 19.6 kPa.


4. Quick Revision Summary

  • Fluid basics – Liquids & gases flow, pressure acts perpendicular to a surface.
  • Hydrostatics – (P = ρgh); deeper → higher pressure.
  • Pascal’s law – Pressure change in a closed fluid transmits uniformly.
  • Archimedes – Buoyant force = weight of displaced fluid.
  • Density – Heavier fluid (higher ρ) exerts more pressure at same depth.
  • Viscosity – Thicker fluids flow slower (important for blood).
  • Continuity – Narrower tubes → faster flow.
  • Bernoulli – Higher speed → lower pressure (used in medical devices).

Tip for exams:
When a question mentions “depth” or “height,” think hydrostatic pressure.
When it mentions “flow through a tube,” use continuity or Bernoulli.
For “floating” or “sinking,” apply Archimedes’ principle.

Good luck! 🚑

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