Chemical Bonding – GPAT Study Notes
(Chemistry – General Pharmacy Aptitude Test)
1. Simple Explanation
Chemical bonding is the attractive interaction that holds atoms together in a molecule or solid.
Three main types:
| Bond type | Key feature | Typical example |
|---|---|---|
| Ionic | Electron transfer → charged ions | NaCl |
| Covalent | Electron sharing | H₂, CH₄ |
| Metallic | Delocalised “sea” of electrons | Cu, Fe |
- Electronegativity (χ) determines how strongly an atom attracts shared electrons.
- Bond polarity arises when the two atoms have different χ.
- Hybridisation explains the shape of covalent bonds (sp, sp², sp³, etc.).
- Molecular Orbital (MO) theory provides a more accurate picture of bonding, bond order, and magnetism.
2. Key Points
| Topic | Key Points |
|---|---|
| Ionic Bonding | • Formed between metal (low χ) and non‑metal (high χ). • Electrons transfer → cation + anion. • Strong electrostatic attraction → high melting/boiling points. • Dissolves in polar solvents → conducts electricity. |
| Covalent Bonding | • Shared electrons between non‑metals. • Single, double, triple bonds – 2, 4, 6 electrons shared. • Polarity depends on Δχ: • Δχ < 0.5 → non‑polar • 0.5 < Δχ < 1.7 → polar covalent • Δχ > 1.7 → ionic‑like (often considered ionic). • Lewis structures: dots for valence electrons. |
| Hybridisation | • Mixing of atomic orbitals to form new hybrid orbitals. • sp → 2 linear → 180°. • sp² → 3 trigonal planar → 120°. • sp³ → 4 tetrahedral → 109.5°. • Determines bond angles and molecular geometry. |
| VSEPR Theory | • Electron‑pair geometry predicted from the number of electron domains around the central atom. • Shapes: Linear, Trigonal Planar, Tetrahedral, Trigonal Bipyramidal, Octahedral. • Bond angles modified by lone pairs (e.g., H₂O → 104.5°). |
| Metallic Bonding | • Delocalised electrons in a lattice of positive ions. • Good electrical and thermal conductivity. • Malleable & ductile. |
| Coordinate (Dative) Covalent Bond | • Both electrons donated by the same atom. • Forms in complexes (e.g., NH₃ → NH₄⁺). |
| Hydrogen Bond | • H attached to highly electronegative atom (F, O, N) interacting with lone pair on another electronegative atom. • Strength: 5–30 kJ mol⁻¹. • Important for water properties, DNA base pairing. |
| Bond Energy & Enthalpy | • Bond dissociation energy (BDE) = energy to break a bond in gas phase. • Bond enthalpy of formation → ΔH_f° of compounds. |
| Molecular Orbital (MO) Theory | • Bonds formed by constructive interference → bonding MO. • Antibonding MO from destructive interference. • Bond order = (n_bonding – n_antibonding)/2. • Predicts magnetic properties (paramagnetic vs diamagnetic). |
3. Worked Example
Problem
Predict the type of bond, bond polarity, and molecular geometry for nitrous oxide (N₂O).
Also, draw its Lewis structure and determine the hybridisation of the central atom.
Step‑by‑Step Solution
| Step | Action | Result |
|---|---|---|
| 1. Identify atoms & valence electrons | N (5 e⁻), O (6 e⁻) → total 5+5+6 = 16 e⁻ (including the lone pair on terminal N). | 16 valence electrons. |
| 2. Arrange atoms | Linear arrangement suggested by formula N–N–O. | |
| 3. Draw single bonds | N–N (1 e⁻ each side) + N–O (1 e⁻). Count 6 e⁻ used. | |
| 4. Complete octets | Remaining 10 e⁻ → 5 lone pairs. Place 2 on O, 3 on terminal N, 0 on central N. | |
| 5. Check formal charges | Terminal N: 5 valence – (3 lone + 1 bond × 1/2) = 0. Central N: 5 – (0 lone + 2 bonds × 1/2) = +1. O: 6 – (4 lone + 1 bond × 1/2) = –1. | |
| 6. Adjust for minimum F.C. | Replace one N–O single bond with a double bond → N–O double, N–N single. Now F.C. of central N becomes 0. | |
| **7 |