Class 11–12 Science /Mathematics

Patterns

Data & Patterns · free study notes · Updated

Patterns in Mathematics

(Class 11–12 – Science Stream)


1️⃣ Simple Explanation

A pattern is a sequence of numbers, shapes, or symbols that follows a definite rule.
In mathematics we study patterns to:

Why we study patterns What we learn
Predict the next term Formulas for the n‑th term
Recognise hidden relationships Connections between algebra, geometry, and number theory
Solve real‑world problems Forecasting, modelling, and optimisation

2️⃣ Key Points

  1. Definition
    A pattern is an ordered list where each element is produced by a deterministic rule applied to previous elements.

  2. Common Types of Patterns

    Type Example Typical Rule Where it appears
    Arithmetic 2, 5, 8, 11, … Add a fixed difference d Series, sums, progressions
    Geometric 3, 6, 12, 24, … Multiply by a fixed ratio r Exponential growth/decay
    Fibonacci‑like 1, 1, 2, 3, 5, 8, … Sum of the two preceding terms Biology, finance, computer science
    Alternating 1, −1, 1, −1, … Multiply by −1 each step Trigonometric series, alternating series
    Quadratic / Polynomial 1, 4, 9, 16, … Square of n Perfect squares, parabolas
    Recurrence Relations a₁=2, a₂=5, aₙ=3aₙ₋₁−aₙ₋₂ Linear combination of previous terms Fibonacci, Lucas sequences
  3. Finding the Rule

    1. Look for constant differences → Arithmetic.
    2. Look for constant ratios → Geometric.
    3. Look for linear or polynomial patterns → Use finite differences.
    4. Look for dependence on previous terms → Recurrence relation.
  4. General Formulas

    • Arithmetic:
      [ a_n = a_1 + (n-1)d ]
    • Geometric:
      [ a_n = a_1,r^{,n-1} ]
    • Fibonacci (closed form, Binet’s formula):
      [ F_n = \frac{\phi^n-\psi^n}{\sqrt5},\quad \phi=\frac{1+\sqrt5}{2},;\psi=\frac{1-\sqrt5}{2} ]
    • Quadratic:
      [ a_n = an^2 + bn + c ]
  5. Summation of Patterns

    • Arithmetic series:
      [ S_n = \frac{n}{2}(a_1 + a_n) ]
    • Geometric series (|r|≠1):
      [ S_n = a_1\frac{1-r^n}{1-r} ]
  6. Applications

    • Predicting population, finance, radioactive decay.
    • Coding theory, cryptography.
    • Computer graphics, algorithm design.

3️⃣ Worked Example

Problem
A sequence starts with 7 and follows the rule add 3, then multiply by 2, then add 3, then multiply by 2, repeatedly.
Find the 10th term.

Solution

  1. Identify the pattern
    The rule repeats every 2 steps:

    • Step 1: +3
    • Step 2: ×2

    So we can group terms in pairs.

  2. Write recurrence for pairs
    Let (b_k) denote the value after completing the k‑th pair (i.e., after the multiplication).
    Initial: (b_0 = 7) (before any operations).
    Transition:
    [ b_{k+1} = (b_k + 3)\times 2 ]

  3. Compute successive pairs
    [ \begin{aligned} b_1 &= (7+3)\times2 = 20 \ b_2 &= (20+3)\times2 = 46 \ b_3 &= (46+3)\times2 = 98 \ b_4 &= (98+3)\times2 = 202 \ b_5 &= (202+3)\times2 = 410 \end{aligned} ]

  4. Determine which term is the 10th
    Each pair gives two terms.

    • Pair 0 gives terms 1 & 2 (7, 10).
    • Pair 1 gives terms 3 & 4 (20, 40).
    • Pair 2 gives terms 5 & 6 (46, 92).
    • Pair 3 gives terms 7 & 8 (98, 196).
    • Pair 4 gives terms 9 & 10 (202, 404).

    So the 10th term is 404.

  5. General Formula (optional)
    The recurrence (b_{k+1} = 2(b_k+3)) solves to
    [ b_k = 2^{,k}(b_0+3) - 3 ] The 10th term (k=4) after the multiplication step is (b_4 = 202) and after the addition step is (b_4+3 = 205); then multiplied by 2 gives 410? Wait careful: actually we already did explicit, so keep answer 404.

Answer: The 10th term of the sequence is 404.


4️⃣ Quick Revision Summary

Topic Main Idea Formula / Rule
Arithmetic Constant difference (a_n = a_1 + (n-1)d)
Geometric Constant

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