M.Sc. Physics – Foundation & Exam Strategy
Topic: Marking Scheme
1️⃣ Simple Explanation
A marking scheme is the rubric or scoring guide that examiners use to award points for each question.
It tells you:
- How many marks a question is worth.
- What specific elements (definitions, equations, reasoning, calculations, conclusions) earn points.
- How partial credit is allocated for incomplete or partially correct answers.
Why it matters:
- It lets you plan how to tackle each question.
- It indicates which parts of the answer are essential for full marks.
- It helps you manage time by prioritising high‑value marks.
2️⃣ Key Points (What to Look For)
| Element | Typical Marking Details | Practical Tips |
|---|---|---|
| Total Marks per Question | Usually 1–10 marks, sometimes split into sub‑parts. | ✓ Write down the total marks before answering. |
| Mark Allocation | Breakdown of points for: • Definition/statement • Explanation/derivation • Calculation • Final answer & units • Physical interpretation |
✓ Highlight or underline the marks you aim to secure. |
| Partial Credit | Points for partially correct steps (e.g., correct formula but wrong substitution). | ✓ Even if you can’t finish, try to earn partial marks. |
| Marking Criteria | Descriptors like “Logical reasoning”, “Correct units”, “Clear notation”, “Correct significant figures”. | ✓ Read the criteria carefully; it tells you what the examiner values. |
| Common Patterns | 1. Short answer – 1–3 marks (definition, brief explanation). 2. Problem solving – 4–10 marks (equations, calculations, final answer). 3. Essay / Discussion – 10–20 marks (structured argument, depth). |
✓ Match your answer length to the expected marks. |
| Time Allocation | 1 mark ≈ 2–3 min, 5 marks ≈ 10–15 min (varies by exam board). | ✓ Use the scheme to split your time. |
| Re‑checking | After answering, verify you’ve hit every sub‑mark. | ✓ Quickly scan the scheme later to see if you missed anything. |
3️⃣ Worked Example
Question (Total 10 marks)
Q1. A particle of mass (m = 2.0;\text{kg}) is launched vertically upward with an initial speed (u = 15;\text{m s}^{-1}). Neglect air resistance.
a) Find the maximum height reached. (4 marks)
b) Determine the time taken to reach that height and the time to return to the launch point. (6 marks)
Provided Marking Scheme
| Part | Marks | What earns marks |
|---|---|---|
| a) | 4 | • Correct kinematic equation (2) • Correct substitution of values (1) • Correct numerical result with units (1) |
| b) | 6 | • Correct formula for time to reach max height (2) • Correct substitution (1) • Correct calculation & units (1) • Correct formula for return time (2) • Correct substitution (1) • Correct final result with units (1) |
(Note: Partial credit available for each sub‑step.)
Answer – How to Score Full Marks
a) Maximum Height (4 marks)
- Equation: (h = \frac{u^2}{2g}) (2 marks)
- Substitution: (u = 15 ;\text{m s}^{-1},; g = 9.8 ;\text{m s}^{-2}) → (h = \frac{(15)^2}{2 \times 9.8} = \frac{225}{19.6} = 11.48 ;\text{m}) (1 mark)
- Result & Units: (h = 11.5 ;\text{m}) (rounded) (1 mark)
b) Time to Reach Height & Return (6 marks)
- Time to top: (t_{\text{up}} = \frac{u}{g} = \frac{15}{9.8} = 1.53 ;\text{s}) (2 marks for formula)
- Substitution: (u, g) → (t_{\text{up}} = 1.53,\text{s}) (1 mark)
- Calculate & Units: (t_{\text{up}} = 1.53 ;\text{s}) (1 mark)