Simple & Compound Interest – Study Notes
(For Lakshadweep Patwari / Lekhpal – Quantitative Aptitude)
1. Simple Explanation
| Concept | What it means | When it is used |
|---|---|---|
| Simple Interest (SI) | Interest earned only on the original principal. | Short‑term loans, savings at fixed rate, when the rate is quoted per annum. |
| Compound Interest (CI) | Interest earned on the principal and on the interest that has already accumulated. | Savings, loans with periodic compounding (annually, semi‑annually, quarterly, monthly, daily). |
| Rate (r) | Annual rate of interest expressed as a percentage. | |
| Time (T) | Number of years (or fraction of a year) the money is invested/borrowed. | |
| n | Number of times interest is compounded in one year (n = 1, 2, 4, 12, 365, …). | |
| Principal (P) | The initial amount of money. | |
| Maturity Value / Amount (A) | Total amount after interest is added. | |
| Interest (I) | The extra money earned or paid. |
Key idea – In simple interest the “interest on interest” never happens; in compound interest it does (once per compounding period).
2. Key Points & Formulas
| Type | Formula | Explanation |
|---|---|---|
| Simple Interest | SI = P × R × T / 100 |
P = principal, R = annual rate, T = time in years. |
| Amount (A) | A = P + SI = P (1 + R T / 100) |
Final amount after simple interest. |
| Compound Interest | CI = P × [(1 + r/n)^(nT) – 1] |
r = annual rate in decimal (e.g., 8 % → 0.08). |
| Amount (A) | A = P × (1 + r/n)^(nT) |
Final amount after compound interest. |
| Effective Annual Rate (EAR) | EAR = (1 + r/n)^n – 1 |
Gives the annual yield if compounded n times. |
| Continuous Compounding | A = P × e^(rT) |
e ≈ 2.71828. |
| Rule of 72 | Years to double ≈ 72 ÷ R |
Quick estimate of doubling time for simple interest. |
| Present Value (Discount) | PV = A / (1 + r/n)^(nT) |
Value today of a future amount A. |
Common Variations
| Scenario | Formula |
|---|---|
| Interest compounded semi‑annually | n = 2 |
| Quarterly | n = 4 |
| Monthly | n = 12 |
| Daily | n = 365 |
| Discount on a future amount | PV = A / (1 + r) * T (simple discount) |
3. Worked Example
Problem
A person deposits ₹10,000 in a bank that pays 8 % per annum compounded quarterly for 3 years.
What will be the maturity amount? What is the compound interest earned?
Step‑by‑step
-
Identify variables
- Principal
P= ₹10,000 - Annual rate
r= 8 % = 0.08 (decimal) - Time
T= 3 years - Compounding frequency
n= 4 (quarterly)
- Principal
-
Compute the factor
[ (1 + r/n)^{nT} = \left(1 + \frac{0.08}{4}\right)^{4 \times 3} = \left(1 + 0.02\right)^{12} = 1.02^{12} ] -
Calculate
1.02^12- Using a calculator:
1.02^12 ≈ 1.268241.
- Using a calculator:
-
Find the maturity amount
A
[ A = P \times 1.268241 = 10,000 \times 1.268241 ≈ ₹12,682.41 ] -
Find the compound interest earned
[ CI = A - P = 12,682.41 - 10,000 = ₹2,682.41 ]
Answers
| Quantity | Value |
|---|---|
Maturity Amount (A) |
₹12,682.41 |
Compound Interest (CI) |
₹2,682.41 |
Quick Check
- Formula used:
A = P × (1 + r/n)^(nT) - **