Lakshadweep Forest Guard /Quantitative Aptitude

Time & work

Commercial Maths · free study notes · Updated

Time & Work – Quantitative Aptitude

Program: Lakshadweep Forest Guard
Topic: Time & Work

“Time & Work” problems ask you to find how long it takes to finish a job, or how much work is done in a given time, when two or more people (or machines) are working together or separately.


1. Simple Explanation

Concept What it means Example
Work The total amount of job that must be done. It can be thought of as “1 job” or “100 % of the job”. W = 1 (one whole task)
Rate of work How much of the job a person (or team) can finish in one unit of time. Person A does 1/8 of the job in one day → Rateₐ = 1/8 job/day
Time How long it takes to complete the job. If A alone takes 8 days → Tₐ = 8 days
Work‑Rate‑Time relation Work = Rate × Time For A: 1 = (1/8) × 8

When multiple people work together, their rates add up.
When someone leaves earlier, you adjust the time they actually worked.


2. Key Points (Quick Reference)

# Formula What to calculate Notes
1 Rate = Work / Time Rate of a person If Work = 1 → Rate = 1/Time
2 Time = Work / Rate How long it takes for one person Time = 1 / Rate
3 Work = Rate × Time Amount of work done in a given time Useful for partial work
4 Combined Rate = Rate₁ + Rate₂ + … Rate when several people work together Add the individual rates
5 Total Work = Combined Rate × Time Work done by a group in a period If they work for t days
6 Work Left = Total Work – Work Done Remaining work Usually Work Left = 1 – Work Done
7 Fraction of work done Rate × Time (e.g., 0.25 of job) Express as a decimal or fraction

Approach to Solve a Problem

  1. Identify the total work – usually 1 job (100 %).
  2. Convert given times or rates into a common unit (days, hours, etc.).
  3. Compute rates for each worker using Rate = 1 / Time if only time is given.
  4. Add rates if workers work together.
  5. Use the total time worked to find work done (Rate × Time).
  6. Subtract from 1 to find the remaining work.
  7. If a worker leaves, multiply his/her rate by the actual time worked.
  8. Solve for unknown time using Time = Work / Rate.

3. Worked Example

Problem (Typical of Forest Guard exam)

A can finish a piece of work in 8 days. B can finish the same work in 12 days.
A and B work together for 2 days. After that, A leaves.
How many more days will B need to finish the remaining work?

Step‑by‑Step Solution

Step Calculation Result
1 Rate of A: (R_A = \dfrac{1}{8}) jobs/day (0.125) jobs/day
2 Rate of B: (R_B = \dfrac{1}{12}) jobs/day (0.0833) jobs/day
3 Combined rate for first 2 days: (R_{AB} = R_A + R_B = 0.125 + 0.0833 = 0.2083) jobs/day
4 Work done in 2 days: (W_{done} = R_{AB} \times 2 = 0.2083 \times 2 = 0.4166) jobs ≈ 41.67 % of the job
5 Work remaining: (W_{left} = 1 - 0.4166 = 0.5834) jobs ≈ 58.34 % of the job
6 B’s rate alone: (R_B = 0.0833) jobs/day
7 Time for B to finish remaining work: (T_B = \dfrac{W_{left}}{R_B} = \dfrac{0.5834}{0.0833} ≈ 7.0) days 7 days

Answer: B needs 7 more days to finish the remaining work.


4. Quick Revision Summary

  1. Work = 1 job (or 100 %)
  2. Rate (per day) = 1 / Time of the worker alone
  3. Combined Rate = Sum of individual rates
  4. Work done = Rate × Time
  5. Time needed = Remaining Work / Rate
  6. Remember:
    • Convert all times to the same unit (days usually).
    • Add rates when people work together.
    • Subtract the work done from 1 to get the remaining work.
    • When someone leaves, use the actual time they worked, not the full schedule.

Quick Practice Question

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