AP EAMCET /Chemistry

d- and f-Block Elements

Inorganic Chemistry - II · free study notes · Updated

d‑ and f‑Block Elements

AP EAMCET – Chemistry


1. Simple Explanation

  • d‑block (transition metals) – Elements whose d subshell is being filled.
  • f‑block (inner transition metals) – Elements whose f subshell is being filled; divided into
    • Lanthanides (4f) – 57 – 71
    • Actinides (5f) – 89 – 103
  • They sit in the middle of the periodic table (blocks B, D, F).
  • Both blocks exhibit a wide range of oxidation states, coloured compounds, and catalytic activity.

2. Key Points

Feature d‑Block f‑Block
Electronic configuration ( (n-1)d^{x} ns^{2} ) ( (n-2)f^{x} (n-1)d^{0–1} ns^{2} )
Common oxidation states +1, +2, +3, +4, +5, +6 (varies) +3 (rare), +4, +5, +6 (actinides), often +3 in lanthanides
Colour Many are colourful due to d‑d transitions (e.g., Fe²⁺ – orange) Lanthanides often sharp‑emission; actinides emit due to f‑f transitions
Magnetic behaviour Paramagnetic (unpaired d electrons) Paramagnetic (unpaired f electrons)
Nuclear magnetic resonance Poor (paramagnetic broadening) Poor (paramagnetic)
Uses Catalysts (e.g., Pt, Pd), pigments, magnetic alloys, electronics Rare‑earth magnets, phosphors, nuclear fuel, catalysts (actinides)
Stability Often high‑valence states are unstable in aqueous media +3 is most stable for lanthanides; actinides show variable valence
Location Periods 4–7, groups 3–12 Lanthanide row below period 6; Actinide row below period 7

Periodic Trends (d‑Block)

  • Atomic radius – decreases across a period, increases down a period (incomplete shielding).
  • Ionisation energy – similar trend, but varies due to electronic configuration.
  • Metallic character – increases down a group.

Periodic Trends (f‑Block)

  • Lanthanide contraction – gradual decrease in ionic radii from La³⁺ to Lu³⁺.
  • Actinide contraction – similar but slightly less pronounced.

3. Worked Example

Problem

Determine the electronic configuration of ( \mathrm{Co^{3+}} ) and its number of unpaired electrons.

Solution

  1. Ground‑state configuration of Co (Z = 27):
    [ \mathrm{Co} : [Ar],4s^{2},3d^{7} ]

  2. Remove 3 electrons to form ( \mathrm{Co^{3+}} ):

    • First, remove the two 4s electrons → (4s^{0}).
    • Then remove one 3d electron → (3d^{6}).

    [ \mathrm{Co^{3+}} : [Ar],3d^{6} ]

  3. Predict electron pairing using Hund’s rule:

    • Five 3d orbitals.
    • With 6 electrons → one orbital will have a paired set, others single.
    Orbital Occupancy Pairing?
    (d_{xy}) 2 yes
    (d_{yz}) 1 no
    (d_{xz}) 1 no
    (d_{z^2}) 1 no
    (d_{x^2-y^2}) 1 no
  4. Number of unpaired electrons: 4.

  5. Result:
    [ \mathrm{Co^{3+}} : [Ar],3d^{6} \quad \text{(4 unpaired e⁻)} ]

Quick check: In an octahedral complex, ( \mathrm{Co^{3+}} ) is often low‑spin (no unpaired electrons). Our free‑ion calculation gives 4 unpaired electrons; ligand field effects would change this.


4. Quick Revision Summary

Topic Points to Remember
Where they sit d‑block: groups 3–12, periods 4–7; f‑block: lanthanides (La‑Lu), actinides (Ac‑Lr)
Electronic config d‑block: ((n-1)d^{x}ns^{2})
Common oxidation states Transition metals: +1 to +6; Lanthanides: +3; Actinides: +3 to +6
Colour & magnetism d‑d (transition metals) → colourful, paramagnetic; f‑f (inner) → sharp emission, paramagnetic
Uses Catalysts, pigments, magnetic alloys, rare‑earth magnets, nuclear fuel
**Trends

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