Class 10 (CBSE) /Mathematics

Coordinate Geometry

Coordinate Geometry · free study notes

Coordinate Geometry – Class 10 (CBSE)

Why this topic?
Coordinate geometry turns geometric problems into algebraic ones. All the concepts you learn here are reused in higher‑level math, physics, engineering and many competitive exams (IIT‑JEE, NPTEL, etc.). Mastering the derivations and tricky points will give you a solid base for those exams.


1. The Cartesian Plane

Symbol Meaning
(x , y) A point in the plane
x‑axis Horizontal axis (positive to the right)
y‑axis Vertical axis (positive upwards)
Origin O (0, 0)
Quadrants I (+,+), II (−,+), III (−,−), IV (+,−)

Note: The first coordinate is the abscissa (x‑coordinate), the second is the ordinate (y‑coordinate).


2. Distance Between Two Points

Formula

[ d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} ]

Derivation

  1. Consider the right‑angled triangle formed by the two points and the perpendiculars to the axes.

  2. By Pythagoras:

    [ d^2 = (x_2-x_1)^2 + (y_2-y_1)^2 ]

  3. Take the square root to get (d).

Key points

  • Works for any two points, even if they lie in different quadrants.
  • If (x_1=x_2) → vertical line → distance is (|y_2-y_1|).
  • If (y_1=y_2) → horizontal line → distance is (|x_2-x_1|).

3. Mid‑Point of a Segment

Formula

[ M!\left(\frac{x_1+x_2}{2},; \frac{y_1+y_2}{2}\right) ]

Derivation

Average the coordinates of the endpoints; the midpoint is exactly halfway along the segment.


4. Slope of a Line

Definition

[ m = \frac{\text{rise}}{\text{run}} = \frac{y_2-y_1}{x_2-x_1} ]

Derivation

  • From two points (P(x_1,y_1)) and (Q(x_2,y_2)), the change in y over the change in x gives the steepness.
  • For a horizontal line, (y_2=y_1) → (m=0).
  • For a vertical line, (x_2=x_1) → slope is undefined (or “infinite”).

5. Equations of a Straight Line

Form General Equation When to use
Point‑Slope (y-y_1 = m(x-x_1)) Given a point and slope
Slope‑Intercept (y = mx + c) Given slope & y‑intercept (c)
General (Ax + By + C = 0) For algebraic manipulation
Intercept (\frac{x}{a} + \frac{y}{b} = 1) Given x‑ and y‑intercepts ((a,0)) and ((0,b))

Derivations

  1. Point‑Slope
    From two points (P(x_1,y_1)) and (Q(x_2,y_2)):

    [ m = \frac{y_2-y_1}{x_2-x_1} \quad\Rightarrow\quad y-y_1 = m(x-x_1) ]

  2. Slope‑Intercept
    Let (c) be the y‑intercept (value of y when (x=0)). The line’s slope is (m).

  3. General
    Multiply the slope‑intercept by a common denominator to clear fractions; bring all terms to the left.

  4. Intercept
    If a line cuts the axes at ((a,0)) and ((0,b)), then:

    [ \frac{x}{a} + \frac{y}{b} = 1 ]

    (Derives from solving for the line passing through those two points.)


6. Parallel & Perpendicular Lines

Property Parallel Perpendicular
Slopes Same ((m_1=m_2)) Product (-1) ((m_1m_2=-1))
Condition for vertical/horizontal If one is vertical, the other also vertical. If one is vertical, the other horizontal.

Example
Given line (y = 3x + 5):

  • Parallel line: (y = 3x + c) (any (c)).
  • Perpendicular line: (y

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