Laws of Motion
Study Notes – TS EAMCET (Physics)
1. Simple Explanation
The laws of motion (Newton’s laws) describe the relationship between a body’s motion and the forces acting upon it. They are the foundation of classical mechanics and allow us to predict how objects will move when forces are applied.
| Law | Statement (in plain words) | Key Idea |
|---|---|---|
| 1st | An object at rest stays at rest, and an object in motion continues with a constant velocity unless acted upon by a net external force. | Inertia – resistance to change in motion. |
| 2nd | The acceleration of an object is directly proportional to the net external force and inversely proportional to its mass: F = m·a. | Quantifies how much a force changes motion. |
| 3rd | For every action there is an equal and opposite reaction. | Forces always come in pairs. |
2. Key Points
2.1 First Law (Law of Inertia)
- Definition: A body will keep its state of rest or uniform straight‑line motion unless acted upon by a net external force.
- Implication:
- If all forces cancel (
ΣF = 0), accelerationa = 0. - On a frictionless surface, a car that has no engine will keep moving forever (ideal case).
- If all forces cancel (
- Applications:
- Understanding motion of projectiles, free‑fall, satellites, etc.
- Designing safety features (seatbelts) that counteract sudden stops.
2.2 Second Law (Law of Acceleration)
- Vector equation:
**F_net** = m · **aF_net– vector sum of all external forces.m– mass of the body (scalar).a– acceleration vector.
- Forces to consider:
- Weight
W = m·g(downward). - Normal force
N(perpendicular to surface). - Friction
f = μ_k N(kinetic) orf ≤ μ_s N(static). - Tension
Tin a rope or string. - Air resistance (often negligible at low speeds).
- Weight
- Important Relationships:
- On an incline of angle θ:
- Parallel component of weight:
W_parallel = m g sinθ - Perpendicular component:
W_perp = m g cosθ - Normal force:
N = W_perp(if no vertical acceleration).
- Parallel component of weight:
- Friction on incline:
f = μ_k N = μ_k m g cosθ(if sliding). - Net force along incline:
F_net = W_parallel – f(if the block is sliding downward).
- On an incline of angle θ:
2.3 Third Law (Action‑Reaction)
- Forces always appear in pairs: if body A exerts a force F on body B, body B exerts a force –F on body A.
- Examples:
- Pulling a rope: you feel the reaction force from the rope.
- Rocket propulsion: exhaust gases push the rocket in the opposite direction.
2.4 Common Situations & Formulas
| Situation | Net Force | Acceleration | Notes |
|---|---|---|---|
| Block on horizontal surface (no friction) | F = m a |
a = F/m |
N = mg, f = 0 |
| Block on horizontal surface (kinetic friction) | F_net = F_applied – f_k |
a = (F_applied – μ_k mg)/m |
f_k = μ_k N |
| Block on inclined plane (no friction) | F_net = m g sinθ |
a = g sinθ |
N = mg cosθ |
| Block on inclined plane (friction) | F_net = m g sinθ – μ_k mg cosθ |
a = g (sinθ – μ_k cosθ) |
|
| Hanging mass (pulley) | F_net = m g – T |
a = g – T/m |
Tension from rope |
| Two‑body interaction | F_AB = –F_BA |
m_A a_A = F_AB, m_B a_B = F_BA |
3. Worked Example
Problem Statement
A 10 kg block is pulled horizontally across a rough floor by a constant horizontal force of 50 N. The coefficient of kinetic friction between the block and the floor is 0.2.
(a) Find the block’s acceleration.
(b) Find the block’s velocity after 5 s, assuming it starts from rest.
Assumptions
- The floor is horizontal (θ = 0).
- No other forces except weight, normal force, applied force, and kinetic friction.
- Gravitational acceleration
g = 9.8 m/s².
(a) Acceleration
- Normal force
[ N = m g = 10 \times 9.8 = 98 ,\text{