JEECUP /Physics

Electrostatics

Electrodynamics · free study notes

Electrostatics – Comprehensive Study Notes

(IIT‑JEE / Competitive Exam Focus)

Objective – Provide a rigorous, exam‑oriented exposition of the core concepts of electrostatics, complete with derivations, key formulae, subtle points, and a challenging practice problem.


1. Fundamental Concepts

Topic Key Idea Symbol Units (SI)
Charge Quantised, conservative (q) coulomb (C)
Electric Field Force per unit charge (\mathbf{E}) V m⁻¹
Potential Work per unit charge (V) volt (V)
Capacitance Ability to store charge per potential difference (C) farad (F)
Dielectric Insulating medium that polarises (ε), (ε_r) farad m⁻¹

2. Coulomb’s Law (Vector Form)

[ \boxed{\mathbf{F}{12}=k_e,\frac{q_1q_2}{r^2};\hat{\mathbf{r}}{12}} ]

  • (k_e=\frac{1}{4\pi\varepsilon_0})
  • (\hat{\mathbf{r}}_{12}) points from (q_1) to (q_2).
  • Derivation (Brief) – From empirical measurement of force between two point charges; linear superposition confirms that the field is (\mathbf{E}=\frac{k_e q}{r^2}\hat{\mathbf{r}}).

Tricky Points

  • Direction: field points away from positive charge, towards negative.
  • Sign of (k_e): always positive; sign is carried by the charges.
  • Units consistency: (k_e) in N m² C⁻² → (E) in N C⁻¹ = V m⁻¹.

3. Electric Field of Continuous Charge Distributions

  1. Linear charge density (\lambda)
    [ \mathbf{E}(\mathbf{r})=\frac{1}{4\pi\varepsilon_0}\int\frac{\lambda,\mathrm{d}\ell}{|\mathbf{r}-\mathbf{r}'|^2},\hat{\mathbf{R}} ]

  2. Surface charge density (\sigma)
    [ \mathbf{E}(\mathbf{r})=\frac{1}{4\pi\varepsilon_0}\int\frac{\sigma,\mathrm{d}a}{|\mathbf{r}-\mathbf{r}'|^2},\hat{\mathbf{R}} ]

  3. Volume charge density (\rho)
    [ \mathbf{E}(\mathbf{r})=\frac{1}{4\pi\varepsilon_0}\int\frac{\rho,\mathrm{d}v}{|\mathbf{r}-\mathbf{r}'|^2},\hat{\mathbf{R}} ]

Symmetry shortcut – Use Gauss’s law to avoid integrals when symmetry is high (spherical, cylindrical, planar).


4. Gauss’s Law (Integral & Differential Forms)

Integral Form

[ \boxed{\oint_{\mathcal{S}}\mathbf{E}\cdot\mathrm{d}\mathbf{A}= \frac{Q_{\text{enc}}}{\varepsilon_0}} ]

  • (Q_{\text{enc}}): total free charge inside the closed surface (\mathcal{S}).
  • Application: Compute (\mathbf{E}) for symmetric charge distributions.

Differential Form

[ \boxed{\nabla!\cdot!\mathbf{E}=\frac{\rho}{\varepsilon_0}} ]

  • Useful for deriving Poisson’s and Laplace’s equations.

Tricky Points

  • Gauss’s law counts only free charge – bound charges in dielectrics are handled via (\mathbf{D}).
  • Choice of Gaussian surface: must exploit symmetry; otherwise it becomes a computational nightmare.
  • Units: (\mathbf{E}) in N C⁻¹, (\mathrm{d}\mathbf{A}) in m² → left side in N C⁻¹·m² = N m² C⁻¹, matches right side.

5. Electric Potential

Definition

[ V(\mathbf{r}) \equiv -\int_{\infty}^{\mathbf{r}} \mathbf{E}!\cdot!\mathrm{d}\mathbf{l} ]

  • Reference at infinity where (V=0).
  • For point charge (q): [ \boxed{V(r)=\frac{1}{4\pi\varepsilon_0},\frac{q}{r}} ]

Relation to Field

[ \boxed{\mathbf{E}=-\nabla V} \

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