XAT /Quantitative Ability

Set theory

Modern Maths · free study notes · Updated

📚 Set Theory – Quick Study Notes for XAT (Quantitative Ability)

Why it matters
Set theory is the foundation of many XAT questions: counting problems, probability, logic, and even some “word” puzzles. Knowing the basics lets you tackle Venn diagrams, complement sets, and power‑set problems in seconds.


1. Simple Explanation

A set is a collection of distinct objects (called elements).

  • Notation: { } (curly braces)
  • Example: A = {1, 2, 3}

Key ideas:

  • Subset – every element of one set is in another.
    B ⊆ A means B is a subset of A.
  • Proper subset – subset but not equal.
    B ⊂ A means B is a proper subset of A.
  • Union – all elements in either set.
    A ∪ B = {x | x ∈ A or x ∈ B}
  • Intersection – only elements common to both.
    A ∩ B = {x | x ∈ A and x ∈ B}
  • Complement – everything outside the set (relative to a universal set U).
    Aᶜ = U \ A
  • Power Set – set of all subsets of a set.
    P(A) = {S | S ⊆ A}

De Morgan’s Laws (for complements):

  • (A ∪ B)ᶜ = Aᶜ ∩ Bᶜ
  • (A ∩ B)ᶜ = Aᶜ ∪ Bᶜ

2. Key Points (Bullet‑style Cheat Sheet)

Concept Symbol Definition Quick Tip
Set A, B, … Collection of distinct objects Use curly braces
Element x ∈ A x belongs to A “∈” = “is an element of”
Empty set ∅ No elements `
Universal set U All objects under consideration For complements
Subset B ⊆ A Every element of B is in A If `
Proper subset B ⊂ A Subset and not equal `
Union A ∪ B All elements in either “or”
Intersection A ∩ B Elements common to both “and”
Complement Aᶜ Elements not in A Relative to U
Set difference A \ B Elements in A not in B Same as A ∩ Bᶜ
Power set P(A) All subsets of A If `
Cardinality ` A `
De Morgan’s (A∪B)ᶜ = Aᶜ∩Bᶜ, (A∩B)ᶜ = Aᶜ∪Bᶜ Rules for complements Use to simplify

Venn Diagram Tips

  • Draw 2–3 overlapping circles (for 2–3 sets).
  • Shade regions to represent “in” or “not in”.
  • Helpful for visualizing unions, intersections, and complements.

3. Worked Example (XAT‑Style)

Problem
Let the universal set U = {1, 2, 3, 4, 5, 6, 7, 8}.
Define

  • A = {1, 3, 5, 7}
  • B = {2, 3, 6, 7}
  • C = {4, 5, 6, 7}

Find the following:

  1. |A ∪ B ∩ C|
  2. (A ∩ B)ᶜ
  3. P(A) (list all subsets of A)

Solution

Step 1 – Compute the intersection B ∩ C.
B ∩ C = {6, 7} (elements common to both).

Step 2 – Compute the union A ∪ (B ∩ C).
A ∪ {6,7} = {1,3,5,6,7}.
So |A ∪ B ∩ C| = 5.


Step 3 – Find the complement of (A ∩ B).
First, A ∩ B = {3, 7}.
Complement relative to U:
(A ∩ B)ᶜ = U \ {3,7} = {1,2,4,5,6,8}.


Step 4 – Power set of A.
A has 4 elements → |P(A)| = 2⁴ = 16 subsets.
List them (grouped by size):

Size Subsets
0 {}
1 {1}, {3}, {5}, {7}
2 {1,3}, {1,5}, {1,7}, {3,5}, {3,7}, {5,7}
3 {1,3,5}, {1,3,7}, {1,5,7}, {3,5,7}
4 {1,3,5,7}

Quick Summary of the Answer

  • |A ∪ B ∩ C| = 5

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