📚 Set Theory – Quick Study Notes for XAT (Quantitative Ability)
Why it matters
Set theory is the foundation of many XAT questions: counting problems, probability, logic, and even some “word” puzzles. Knowing the basics lets you tackle Venn diagrams, complement sets, and power‑set problems in seconds.
1. Simple Explanation
A set is a collection of distinct objects (called elements).
- Notation:
{ }(curly braces) - Example:
A = {1, 2, 3}
Key ideas:
- Subset – every element of one set is in another.
B ⊆ Ameans B is a subset of A. - Proper subset – subset but not equal.
B ⊂ Ameans B is a proper subset of A. - Union – all elements in either set.
A ∪ B = {x | x ∈ A or x ∈ B} - Intersection – only elements common to both.
A ∩ B = {x | x ∈ A and x ∈ B} - Complement – everything outside the set (relative to a universal set U).
Aᶜ = U \ A - Power Set – set of all subsets of a set.
P(A) = {S | S ⊆ A}
De Morgan’s Laws (for complements):
(A ∪ B)ᶜ = Aᶜ ∩ Bᶜ(A ∩ B)ᶜ = Aᶜ ∪ Bᶜ
2. Key Points (Bullet‑style Cheat Sheet)
| Concept | Symbol | Definition | Quick Tip |
|---|---|---|---|
| Set | A, B, … |
Collection of distinct objects | Use curly braces |
| Element | x ∈ A |
x belongs to A |
“∈” = “is an element of” |
| Empty set | ∅ |
No elements | ` |
| Universal set | U |
All objects under consideration | For complements |
| Subset | B ⊆ A |
Every element of B is in A |
If ` |
| Proper subset | B ⊂ A |
Subset and not equal | ` |
| Union | A ∪ B |
All elements in either | “or” |
| Intersection | A ∩ B |
Elements common to both | “and” |
| Complement | Aᶜ |
Elements not in A |
Relative to U |
| Set difference | A \ B |
Elements in A not in B |
Same as A ∩ Bᶜ |
| Power set | P(A) |
All subsets of A |
If ` |
| Cardinality | ` | A | ` |
| De Morgan’s | (A∪B)ᶜ = Aᶜ∩Bᶜ, (A∩B)ᶜ = Aᶜ∪Bᶜ | Rules for complements | Use to simplify |
Venn Diagram Tips
- Draw 2–3 overlapping circles (for 2–3 sets).
- Shade regions to represent “in” or “not in”.
- Helpful for visualizing unions, intersections, and complements.
3. Worked Example (XAT‑Style)
Problem
Let the universal set U = {1, 2, 3, 4, 5, 6, 7, 8}.
Define
A = {1, 3, 5, 7}B = {2, 3, 6, 7}C = {4, 5, 6, 7}
Find the following:
|A ∪ B ∩ C|(A ∩ B)ᶜP(A)(list all subsets ofA)
Solution
Step 1 – Compute the intersection B ∩ C.
B ∩ C = {6, 7} (elements common to both).
Step 2 – Compute the union A ∪ (B ∩ C).
A ∪ {6,7} = {1,3,5,6,7}.
So |A ∪ B ∩ C| = 5.
Step 3 – Find the complement of (A ∩ B).
First, A ∩ B = {3, 7}.
Complement relative to U:
(A ∩ B)ᶜ = U \ {3,7} = {1,2,4,5,6,8}.
Step 4 – Power set of A.
A has 4 elements → |P(A)| = 2⁴ = 16 subsets.
List them (grouped by size):
| Size | Subsets |
|---|---|
| 0 | {} |
| 1 | {1}, {3}, {5}, {7} |
| 2 | {1,3}, {1,5}, {1,7}, {3,5}, {3,7}, {5,7} |
| 3 | {1,3,5}, {1,3,7}, {1,5,7}, {3,5,7} |
| 4 | {1,3,5,7} |
Quick Summary of the Answer
|A ∪ B ∩ C| = 5