SSC MTS – Reasoning Ability
Topic: Puzzles
Puzzles are a popular section in the SSC MTS Reasoning Ability paper.
They test your ability to decipher patterns, relationships, and hidden rules from a set of given clues.
In the exam, a puzzle usually appears as a short paragraph or a diagram followed by one or more questions.
1. Simple Explanation
| Term | What it Means | Example |
|---|---|---|
| Clue | A piece of information that helps you deduce the final arrangement or order. | “The person in seat 3 is older than the person in seat 5.” |
| Conditional | A clue that applies only when a certain condition is met. | “If person A sits next to person B, then person C sits opposite person A.” |
| Relative | A clue that compares two or more entities. | “The tallest person is not in the first row.” |
| Absolute | A clue that states a fixed position or attribute. | “Person D sits in seat 4.” |
Goal:
Using the clues, determine the exact arrangement of people, objects, or events.
2. Key Points
| # | Key Point | Why It Matters |
|---|---|---|
| 1 | Read the puzzle twice – first for a quick scan, second for detailed analysis. | Avoid missing hidden relationships. |
| 2 | List all entities (people, seats, colors, etc.) and their possible attributes. | Helps keep track of options. |
| 3 | Create a matrix or a table – each row = entity, each column = attribute. | Easy to cross‑reference clues. |
| 4 | Apply “If‑then” logic systematically. | Prevents contradictory placements. |
| 5 | Use elimination – mark impossible combinations with an “X”. | Reduces complexity. |
| 6 | Check consistency – after each deduction, verify against all clues. | Avoids mistakes that propagate. |
| 7 | Look for “must‑be” clues – those that leave no other option. | Gives the first solid anchor. |
| 8 | Work backward – sometimes it’s easier to start from the conclusion and trace back. | Useful when the final answer is known. |
| 9 | Time‑management – practice solving a puzzle in ≤ 30 sec. | Crucial for the exam. |
| 10 | Re‑read clues after solving – ensure no clue was ignored. | Final sanity check. |
3. Worked Example (Typical SSC MTS Style)
Puzzle Statement
In a room, five men (A, B, C, D, E) are seated in a row from left to right.
- A sits immediately to the right of the man who owns the blue car.
- The man who owns the red car sits next to B.
- C owns the green car.
- The man who owns the yellow car sits at one end.
- E sits next to the man who owns the blue car.
Question: Who owns the blue car?
Step‑by‑Step Solution
| Step | Action | Result |
|---|---|---|
| 1 | Identify fixed positions – “yellow car at one end.” | Seat 1 or Seat 5 → Yellow. |
| 2 | Place C – owns green car. | Green car not at an end (can be 2,3,4). |
| 3 | Consider red car next to B. | Red car cannot be at an end (since it must be next to B). |
| 4 | Blue car adjacency – A sits right of blue car; E sits next to blue car. | Blue car cannot be at end (needs two neighbors). |
| 5 | Test possibilities for blue car – If blue at Seat 2 → A at Seat 3, E at Seat 1 or 3. But Seat 3 already A, so E cannot be at 3 → E at 1. | Works: E at 1 (blue adjacency). |
| 6 | Check B and red car – red car must be next to B. B cannot be at Seat 1 or 5 (ends). | B at Seat 4 → red car at Seat 5 or 3. Seat 5 is yellow, so red car at Seat 3. |
| 7 | Assign remaining – Seat 4 is B; Seat 3 red; Seat 5 yellow; Seat 2 blue; Seat 1 E. | Remaining man C must be at Seat 4? Wait B already at 4. Re‑evaluate: B at 4; Seat 3 red car (owner unknown). Seat 2 blue car (owner unknown). Seat 1 E. Seat 5 yellow (owner unknown). Seat 4 B. Seat 3 cannot be B. So Seat 3 owner = C? But C owns green. So Seat 3 cannot be green. Contradiction. |
We need to backtrack. Let's try blue car at Seat 3.
| Step | Action | Result |
|---|---|---|
| 1 | Blue at Seat 3 → A at Seat 4; E at Seat 2 or 4. Seat 4 already A, so E at 2. | E at 2. |
| 2 | Yellow at an end: Seat 1 or 5. | TBD. |
| 3 | Red car next to B. B cannot be at an end. | B at 3? No (blue). B at 4? No (A). B at 5? Possible. Then red at 4 or 6 (no 6). So red at 4? Seat 4 is A. So B cannot be 5. B must be 1? But 1 is end; red car next to B → seat 2 or 0. Seat 2 is E. So red car at seat 2. |
| 4 | Seat 2 has red car (E). | E owns red car. |
| 5 | C owns green car. | C cannot be at |