SSC JE /General Awareness & Current Affairs

Physics basics

General Science · free study notes · Updated

SSC JE – General Awareness & Current Affairs

Physics Basics – Study Notes

Audience: Candidates preparing for the SSC Junior Engineer (JE) exam.
Objective: Understand the essential concepts of physics that are frequently asked in the exam, especially in the “General Awareness & Current Affairs” paper.


1. Simple Explanation

Physics is the science of matter, energy, and the interactions between them. It explains how objects move, how forces act, how electricity and magnetism work, and how waves and light behave. In the SSC JE exam, physics is mainly tested through basic principles and their application in everyday situations.

Think of physics as the rule book that tells us what happens when we push, pull, heat, or shine light on something.


2. Key Points

Area Key Concept Representative Formula / Law
Classical Mechanics Motion in one dimension s = ut + ½at²
Uniform Circular Motion v = ωr
Newton’s 1st–3rd Laws F = ma (2nd law)
Work & Energy W = F·d; ½mv²
Power P = W/t = Fv
Electricity & Magnetism Ohm’s Law V = IR
Kirchhoff’s Laws ΣI(in) = ΣI(out); ΣV = 0
Magnetic Force F = q(v × B)
Faraday’s Law ε = -dΦ/dt
Waves & Optics Wave Speed v = fλ
Snell’s Law n₁ sinθ₁ = n₂ sinθ₂
Reflection & Refraction Law of Reflection: θᵢ = θᵣ
Interference constructive: 2d = mλ
Thermodynamics First Law ΔU = Q – W
Heat Transfer Q = mcΔT
Carnot Efficiency η = 1 – Tₖ/Tₕ
Modern Physics Photoelectric Effect K = eV₀ = hf – φ
Basic Quantum Idea E = hf
Relativity (basic) E = mc² (mass–energy)

Tip: In SSC JE, you rarely need to derive formulas—just memorize the most common ones above.


3. Worked Example

Problem:
A free‑falling object starts from rest and falls for 3 seconds. What is its velocity and distance travelled?

Solution:

  1. Known data

    • Initial velocity, (u = 0) m/s
    • Acceleration due to gravity, (a = 9.8) m/s²
    • Time, (t = 3) s
  2. Velocity after time (t)
    Use the kinematic equation:
    [ v = u + at ] Plugging the values: [ v = 0 + (9.8 \text{ m/s}^2)(3 \text{ s}) = 29.4 \text{ m/s} ]

  3. Distance travelled
    Use:
    [ s = ut + \tfrac{1}{2}at^2 ] [ s = (0)(3) + \tfrac{1}{2}(9.8)(3)^2 = 0.5 \times 9.8 \times 9 = 44.1 \text{ m} ]

Answer:

  • Final velocity = 29.4 m/s
  • Distance travelled = 44.1 m

4. Quick Revision Summary

Concept Formula Units Note for SSC JE
Linear acceleration (a = \Delta v / t) m/s² Basic, use in kinematics
Uniform speed (v = s/t) m/s Simple division
Force (Newton 2nd) (F = ma) N (kg·m/s²) Fundamental
Work (W = Fd\cos\theta) J (N·m) Cosine term often 1
Power (P = W/t) or (P = Fv) W (J/s) Common in machinery
Ohm’s Law (V = IR) V, A, Ω Essential for electrical circuits
Resistance in series (R_{eq} = R_1+R_2+…) Ω Additive
Resistance in parallel (1/R_{eq} = 1/R_1+1/R_2+…) Ω Reciprocal sum
Wave speed (v = fλ) m/s Frequency × wavelength
Snell’s Law (n_1\sinθ_1 = n_2\sinθ_2) — Refraction in optics
Photoelectric threshold (hf = φ) eV Minimum photon energy
Relativistic mass‑energy (E = mc^2) J Basic concept only

Mnemonic for remembering the first law of thermodynamics:
“Heat in, Work out, Energy change in.”


Final Tips for SSC JE

  1. Memorize the key formulas and their units.
  2. Practice at least one problem per concept each week

Your note

Page 1

Doubt hai is topic me?

Free AI teacher se poocho — 24/7, step by step.