Caselets – A Quick Guide for IBPS PO Quantitative Aptitude
What are Caselets?
In IBPS PO Quantitative Aptitude you will often encounter caselets: a set of 2–3 inter‑related questions that share a common scenario (e.g., “A train travels 200 km at 80 km/h …”).
The answers to later parts may require the result of earlier parts. Mastering caselets saves time and reduces errors.
1. Simple Explanation
- Scenario – A real‑world situation (distance‑speed‑time, profit‑loss, mixture, etc.).
- Multiple Questions – Usually 3 questions (a, b, c) that build on each other.
- Inter‑dependency – The answer of Q(a) often becomes an input for Q(b) and Q(c).
- Key Idea – Solve part (a) first, then use that result in (b) and (c). Keep track of units and significant figures.
2. Key Points & Strategies
| # | Strategy | Why It Works |
|---|---|---|
| 1 | Read the whole caselet first | You’ll know what data each part needs and avoid re‑reading. |
| 2 | Underline or color‑code variables | Helps in quick reference when moving from one part to the next. |
| 3 | Solve part (a) on paper, not mentally | You’ll have the exact number for later parts. |
| 4 | Use the “carry‑over” method | Keep a separate small box for the answer of part (a) and refer to it. |
| 5 | Check units | Mixing km with miles, hours with minutes can lead to wrong answers. |
| 6 | Round only at the end | Prevent cumulative rounding errors. |
| 7 | Double‑check calculations | A small arithmetic slip in part (a) propagates to (b) & (c). |
| 8 | Practice with time constraints | In exam you have ~3–4 min for a caselet; practice speeds up. |
3. Worked Example
Caselet
Scenario
A bus starts from City A and travels at a constant speed of 60 km/h. After 2.5 hours it reaches City B.Questions
(a) What is the distance covered?
(b) If the bus had travelled at 75 km/h for the same distance, how many hours would it take?
(c) The bus then returns to City A at a speed of 45 km/h. What is the total time of the round trip?
Step‑by‑Step Solution
| Part | Calculation | Result |
|---|---|---|
| (a) | Distance = Speed × Time = 60 km/h × 2.5 h | 150 km |
| (b) | Time = Distance ÷ Speed = 150 km ÷ 75 km/h | 2 hours |
| (c) | Return Time = 150 km ÷ 45 km/h = 3.333… h (3 h 20 min) Total Time = 2.5 h + 3.333… h = 5.833… h (5 h 50 min) |
5 h 50 min |
Quick Check
- All calculations used correct units.
- Rounding only at the final answer of part (c).
4. Quick Revision Summary
| What to Remember | Checkpoint |
|---|---|
| Define the scenario first | Can you summarise the situation in one sentence? |
| Answer part (a) precisely | Did you compute the exact value before moving on? |
| Use part (a) in (b) & (c) | Are the numbers from (a) inserted correctly? |
| Keep units consistent | Is km/h, km, and h all used correctly? |
| Avoid premature rounding | Did you round only at the end? |
| Time practice | Can you solve a caselet in ~3–4 min? |
Final Tip
When you see a caselet, write a mini‑plan:
- List variables.
- Solve (a).
- Plug into (b).
- Plug into (c).
Stick to this rhythm, and caselets will become a breeze!