IBPS Clerk /Quantitative Aptitude

Number system

Arithmetic · free study notes

Number System – Advanced Study Notes

Target Exam: IBPS Clerk – Quantitative Aptitude
Level: MIT‑style, first‑principles with rigorous reasoning & edge‑case analysis

Why these notes?
The “Number System” section of IBPS is often the crux of quantitative aptitude. A solid grasp of base‑representation, divisibility, and modular arithmetic not only scores well in the exam but also lays a foundation for higher mathematics.

Structure

  1. Foundations – base‑b representation, conversions, uniqueness.
  2. Rational/irrational expansions – finite vs repeating, period theory.
  3. Divisibility – classical rules and generalizations.
  4. Prime‑number theory – Euclid, Wilson, Fermat.
  5. GCD, LCM, modular arithmetic, Euler’s theorem, CRT.
  6. Edge cases & pitfalls.
  7. Advanced topics & applications.
  8. Practice problems (simple → advanced).
  9. One challenging problem with full solution.

Notation
b – any integer base (b ≥ 2).
n – positive integer.
gcd(a,b) – greatest common divisor.
φ(n) – Euler’s totient function.
ord_b(n) – multiplicative order of b modulo n (smallest k > 0 s.t. b^k ≡ 1 (mod n)).


1. Foundations – Base‑b Representation

1.1 Decimal, Binary, Octal, Hexadecimal

  • Decimal: base 10, digits 0–9.
  • Binary: base 2, digits 0,1.
  • Octal: base 8, digits 0–7.
  • Hexadecimal: base 16, digits 0–9, A–F.

1.2 Representation in Base b

Definition
Any integer N (positive or negative) can be written uniquely as
[ N = \sum_{i=0}^{k} d_i,b^i,\quad d_i\in{0,1,\dots,b-1}, ] where k = ⌊log_b |N|⌋ for N > 0.
For negative numbers, use a minus sign or two’s complement in binary contexts.

Theorem (Uniqueness)
For a fixed base b and fixed digit set, the representation above is unique.

Proof Sketch
Suppose two distinct expansions exist. Subtracting yields a non‑zero integer that is divisible by b but less than b, impossible unless the difference is zero. ∎

1.3 Converting Between Bases

Step Explanation Example (decimal → binary)
1 Divide N by b, record remainder. 13 ÷ 2 = 6 R 1
2 Repeat with quotient until it becomes 0. 6 ÷ 2 = 3 R 0; 3 ÷ 2 = 1 R 1; 1 ÷ 2 = 0 R 

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