LIC ADO /Quantitative Aptitude

Simple & compound interest

Commercial Maths · free study notes · Updated

Simple & Compound Interest – Study Notes

Program: LIC ADO | Subject: Quantitative Aptitude | Topic: Simple & Compound Interest


1. Simple Explanation

Concept What it Means When It Is Used
Simple Interest (SI) Interest calculated only on the original principal. Short‑term loans, simple savings accounts, quick calculations.
Compound Interest (CI) Interest is calculated on the principal + accumulated interest. Long‑term investments, bank deposits, loans with compounding.

Key Insight:

  • SI grows linearly (adds a fixed amount each period).
  • CI grows exponentially (interest on interest).

2. Key Points

Item Detail Quick Tip
Formula for SI ( I = P \times r \times t )
( M = P + I = P(1 + rt) )
r is annual rate in decimal, t in years.
Formula for CI ( A = P \left(1 + \frac{r}{n}\right)^{nt} ) n = compounding periods per year (e.g., 4 = quarterly).
Annual Effective Rate ( (1 + \frac{r}{n})^n - 1 ) Use to compare different compounding frequencies.
Continuous Compounding ( A = P e^{rt} ) Use when compounding is “infinitely frequent”.
Difference (Δ) ( CI - SI = P \left[(1+\frac{r}{n})^{nt} - (1+rt)\right] ) Shows the “interest‑on‑interest” benefit.
Principal (P) Initial amount invested or borrowed. Keep track of units (₹, $, etc.).
Rate (r) Annual interest rate (decimal). 8 % → 0.08.
Time (t) Number of years. Convert months: ( t = \frac{m}{12} ).
Compounding Frequency (n) How often interest is added per year. n = 1 (annually), 2 (semi‑annually), 4 (quarterly), 12 (monthly).
Maturity Value (A) Total amount at the end of the investment period. For loans, this is the total amount to be repaid.
Interest Earned (I) ( A - P ) for CI; ( P r t ) for SI. Always double‑check units.
Common Pitfalls 1. Forgetting to convert percentages to decimals.
2. Mixing up compounding periods.
3. Using SI formula for compounding scenario.
Always label each variable.

3. Worked Example

Example 1 – Simple Interest

Problem:
Invest ₹12,000 at an annual simple interest rate of 7 % for 3 years.
What is the maturity value?

Solution:

  1. Convert rate: ( r = 7% = 0.07 )
  2. Compute interest:
    [ I = P \times r \times t = 12{,}000 \times 0.07 \times 3 = 2{,}520 ]
  3. Maturity value:
    [ M = P + I = 12{,}000 + 2{,}520 = 14{,}520 ]

Answer: ₹14,520


Example 2 – Compound Interest

Problem:
Deposit ₹15,000 in a bank account that pays 6 % annual interest compounded quarterly for 4 years.
What will be the balance at the end of the period?

Solution:

  1. Convert rate: ( r = 6% = 0.06 )
  2. Compounding frequency: ( n = 4 )
  3. Time: ( t = 4 ) years
  4. Apply CI formula:
    [ A = P \left(1 + \frac{r}{n}\right)^{nt} = 15{,}000 \left(1 + \frac{0.06}{4}\right)^{4 \times 4} ]
    [ A = 15{,}000 \left(1 + 0.015\right)^{16} = 15{,}000 \

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