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Limits & continuity

Calculus · free study notes · Updated

Limits & Continuity – Study Notes

(For PSU / GATE Mathematics)

Aim – Understand the formal definition of limits, continuity, and common techniques to evaluate them.


1. Simple Explanation

Concept Intuition Formal Statement
Limit As (x) gets arbitrarily close to (a), the function (f(x)) approaches a value (L). (\displaystyle \lim_{x\to a} f(x)=L) iff for every (\varepsilon>0) there exists (\delta>0) such that [0<
Continuity at (a) No “jump” or “hole” at (x=a); the function value equals the limit. (f) is continuous at (a) iff (\displaystyle \lim_{x\to a} f(x)=f(a).)
Right / Left limits Approach from one side only. (\displaystyle \lim_{x\to a^+} f(x)=L^+), (\displaystyle \lim_{x\to a^-} f(x)=L^-).
Discontinuity types “Removable”, “Jump”, “Infinite”, “Oscillatory”.

2. Key Points

Topic Key Points
Existence of Limits 1. If (\lim_{x\to a}f(x)) exists, both one‑sided limits exist and are equal.
2. If either one‑sided limit diverges, the two‑sided limit does not exist.
Limit Laws (i) (\lim (f+g)=\lim f+\lim g)
(ii) (\lim (fg)=\lim f\cdot\lim g)
(iii) (\lim\frac{f}{g}=\frac{\lim f}{\lim g}) (provided (\lim g\neq0))
(iv) (\lim c f = c\lim f)
Continuity Properties 1. Sum, product, quotient (with non‑zero denominator) of continuous functions are continuous.
2. Composition (g\circ f) is continuous if (f) is continuous at (a) and (g) is continuous at (f(a)).
Piecewise Functions Check continuity at boundary points by verifying left/right limits and the function value.
Removable Discontinuity Occurs when (\lim_{x\to a}f(x)) exists but (f(a)\neq \lim f). Can be “fixed” by redefining (f(a)).
Jump Discontinuity Left and right limits exist but are unequal.
Infinite Discontinuity At least one one‑sided limit is (\pm\infty).
Oscillatory Discontinuity Limits from either side do not exist due to infinite oscillations.
Continuity on Intervals A function is continuous on ([a,b]) iff it is continuous at every point in ((a,b)) and has one‑sided limits at (a,b).
Important Theorems Intermediate Value Theorem, Bolzano’s theorem, Weierstrass theorem – useful for existence proofs.

3. Worked Example

Problem

Evaluate

[ \lim_{x\to 0} \frac{\sin 3x}{x} ]

and determine whether the function

[ f(x)= \begin{cases} \dfrac{\sin 3x}{x}, & x\neq 0 \ k, & x=0 \end{cases} ]

is continuous at (x=0). If it is not continuous, find the value of (k) that makes it continuous.


Step 1: Use a Standard Limit

Recall the fundamental limit

[ \lim_{u\to 0}\frac{\sin u}{u}=1 . ]

Let (u = 3x). When (x\to 0), (u\to 0), and

[ \frac{\sin 3x}{x} = \frac{\sin u}{u}\cdot 3 ]

since (x = u/3). Therefore,

[ \lim_{x\to 0}\frac{\sin 3x}{x} = \lim_{u\to 0}\left( \frac{\sin u}{u}\right)\cdot 3 = 1\cdot 3 = 3. ]


Step 2: Continuity at (x=0)

For continuity at (0),

[ \lim_{x\to 0}f(x) = f(0). ]

We found (\displaystyle \lim_{x\to 0}f(x) = 3).
Hence (f) is continuous at (0) iff (k=3).

  • If (k=3): (f(0)=3) and (\lim_{x\to0}f(x)=3) → continuous.
  • If (k\neq 3): mismatch → discontinuity (removable).

Step 3: Classify the Discontinuity (if (k\neq3))

The function has a removable discontinuity at (x=0) because:

  • Both one‑sided limits exist (equal to 3).
  • The function value is not equal to this limit.

4. Quick Revision Summary

Topic What to Recall
Limit Definition Epsilon–delta condition.
Limit Laws Sum, product, quotient, scalar multiple.
Continuity at a Point (\lim f = f(a)).
Piecewise Continuity Check left/right limits at boundaries.
Discontinuity Types Removable, jump, infinite, oscillatory.
Continuity on Intervals

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