West Bengal Patwari / Lekhpal /Quantitative Aptitude

Time & work

Commercial Maths · free study notes

Time & Work – Advanced Study Notes

(For West Bengal Patwari / Lekhpal – Quantitative Aptitude)

A Patwari or Lekhpal often deals with schedules, man‑power allocation, and time‑based budgeting. Mastery of the “time & work” concept is therefore essential for civil‑service exams and for practical field work.


1. Foundations – From First Principles

Symbol Meaning Unit
(W) Work (amount of job) “job‑units” (e.g., acres surveyed)
(r) Rate of work job‑units per unit time
(t) Time days, hours, etc.

Basic Relation
[ W = r,t \tag{1} ]

Proof: By definition, rate is the amount of job completed per unit time. Multiply both sides by (t) to obtain the total job.

Rearrangements
[ r = \frac{W}{t},\qquad t = \frac{W}{r} \tag{2} ]

These three formulas are the building blocks for every “time & work” problem.


2. Combined Work – Multiple Workers

When (n) workers work together, rates add:

[ r_{\text{total}} = \sum_{i=1}^{n} r_i \tag{3} ]

Hence, if all workers are required to finish a job (W),

[ t = \frac{W}{\sum r_i} \tag{4} ]

Example
A & B finish 30 acres in 4 days.
(r_A + r_B = \frac{30}{4}=7.5) acres/day.
If A alone can finish 20 acres in 5 days ⇒ (r_A = \frac{20}{5}=4) acres/day.
Therefore (r_B = 3.5) acres/day and (t_B = \frac{30}{3.5}\approx 8.57) days.


3. Partial Work – When Workers Join/Leave

3.1 Worker leaves after completing a part

Let worker A work for (t_a) days at rate (r_a).
Remaining work (W_{\text{rem}} = W - r_a t_a).

If B works at rate (r_b) for the rest,

[ t_b = \frac{W_{\text{rem}}}{r_b} \quad\Rightarrow\quad t_{\text{total}} = t_a + t_b ]

3.2 Worker joins after a delay

If B starts after (d) days, then

[ t_{\text{total}} = d + \frac{W - r_a d}{r_a + r_b} ]

Edge Case – If (r_a + r_b = 0) (both ineffective), the job never finishes.


4. Variable Rates – Work as a Function of Time

In real life, a worker’s efficiency may change (fatigue, weather, learning).
Let (r(t)) be the instantaneous rate at time (t).
Total work done in an interval ([0,T]) satisfies

[ W = \int_{0}^{T} r(t),dt \tag{5} ]

4.1 Piecewise Constant Rate

If the rate changes at known times:

[ W = \sum_{k=1}^{m} r_k ,\Delta t_k ]

4.2 Linear Decrease (example)

Suppose a surveyor starts at 10 acres/day and loses 0.5 acres/day due to fatigue.

[ r(t) = 10 - 0.5 t \quad (t \text{ in days}) ]

Work done in (T) days:

[ W = \int_{0}^{T} (10 - 0.5t),dt = 10T - 0.25T^2 ]

If the job is 75 acres, solve (10T - 0.25T^2 = 75) ⇒ (T = 10) days.


5. Harmonic Mean of Rates – When Each Worker Completes the Same Amount

If (n) workers each finish the same job (W) in times (t_i), their rates are (r_i = W/t_i).
The effective rate when all work together equals the harmonic mean of the individual rates:

[ r_{\text{eff}} = \frac{n}{\displaystyle\sum_{i=1

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