Chhattisgarh Forest Guard /Quantitative Aptitude

Time & work

Commercial Maths · free study notes

Time & Work – Comprehensive Study Notes

(For IIT‑JEE / Competitive Exams)


1. Introduction

Time & Work problems are the bread‑and‑butter of quantitative aptitude.
They test your ability to translate everyday situations into algebraic relationships.
The key is to express everything in terms of “work” (units of job) and “rate” (units of work per unit time).

Definition
Work – the amount of job done.
Rate – work done per unit time.
Time – duration taken to finish a job.


2. Fundamental Relation

[ \boxed{\text{Work} = \text{Rate} \times \text{Time}} ]

or

[ \boxed{ \text{Rate} = \frac{\text{Work}}{\text{Time}} }, \qquad \boxed{ \text{Time} = \frac{\text{Work}}{\text{Rate}} } ]

  • Units:
    Work – a dimensionless “job” (e.g., “1 job”).
    Rate – “job per hour” (or any time unit).
    Time – “hours”, “days”, etc.

3. Combining Rates

When two or more workers/machines work together, their rates add.

[ R_{\text{total}} = R_1 + R_2 + \dots + R_n ]

Hence

[ T_{\text{total}} = \frac{W}{R_{\text{total}}} ]


4. Working in Ratios

If two workers A and B work together and finish a job in 12 hours,
and if A alone were to finish the same job in 20 hours, what would be B’s time?

  1. Compute the individual rates
    [ R_A = \frac{1}{20};\text{job/h}, \quad R_B = \frac{1}{T_B};\text{job/h} ]
  2. Use combined rate
    [ \frac{1}{12} = R_A + R_B = \frac{1}{20} + \frac{1}{T_B} ]
  3. Solve for (T_B).

General trick – When a part of a worker’s time is not used, subtract that time from the given total.


5. Work Done by Machines / Workers with Efficiency

Sometimes the efficiency (or faulty rate) is given.
Let a machine’s nominal rate be (R), but due to a 10 % fault it actually works at (0.9R).
Use the effective rate in all subsequent calculations.


6. Work with Breaks / Shifts

If a worker works in shifts or takes breaks, you simply subtract the unused time from the total.

Example:
Worker A works 8 h/day, breaks 2 h/day, so effective time per day = 6 h.
If he works for 5 days, total effective time = (5 \times 6 = 30) h.


7. Partially Completed Work

When a portion of a job is already done, treat the remaining work as a new problem.

  • Let (W_{\text{total}}) be the whole job.
  • If (x%) is done, remaining work = ( \frac{100-x}{100}, W_{\text{total}}).

8. Work in Changing Rates

A worker may start slower and get faster (or vice versa).
If the rates change in a known ratio, use the average rate.

Example:
Worker works first half at rate (R), second half at rate (2R).
Average rate = (\frac{R + 2R}{2} = 1.5R).


9. Important Formulas (Quick Reference)

Quantity Symbol Formula
Work (W)
Rate (R) (R = \dfrac{W}{T})
Time (T) (T = \dfrac{W}{R})
Combined rate (R_{\text{tot}}) (R_{\text{tot}} = \sum R_i)
Work done in time (t) (W = R \times t)
Remaining work after (p%) done (W_{\text{rem}}) (W_{\text{rem}} = \dfrac{100-p}{100},W)
Effective rate (efficiency (e)) (R_{\text{eff}}) (R_{\text{eff}} = e \times R)
Work by two workers A & B in (t) hours (\displaystyle \frac{t}{T_A} + \frac{t}{T_B})

10. Tricky

Your note

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