Puducherry Patwari / Lekhpal /Quantitative Aptitude

Time & work

Commercial Maths · free study notes

Time & Work – Advanced Study Notes

(quantitative aptitude, “Time & Work”)

Target audience – Undergraduate students (MIT‑level or equivalent).
Goal – Build a solid mathematical foundation, explore edge cases, and develop the ability to solve and design advanced problems.


1. Introduction

“Time & Work” problems ask us to determine how long it takes for one or more workers (or machines, processes, etc.) to finish a task, based on their rates of work.
The problems are ubiquitous in engineering, operations research, and applied mathematics.
At the university level we treat the following general framework:

Symbol Meaning Units Notation
(W) Total amount of work (tasks, units, distance, etc.) unit (W)
(r_i) Rate of worker (i) unit/time (r_i)
(t) Time elapsed time (t)
(n) Number of workers – (n)
(A) Work area under a rate‑vs‑time curve unit –

Fundamental law (the rate rule):
[ \text{Work done} = \int_0^t r(\tau), d\tau ] If each worker works at a constant rate (r_i) over the interval ([0,t]), the total work is simply [ W = t\sum_{i=1}^n r_i. ] This is the starting point for all “time & work” problems.


2. Basic Algebraic Treatment

2.1 Single worker

If worker (A) can finish a job in (T) hours, his rate is [ r_A = \frac{W}{T}. ] If we know (r_A), the time it takes to finish the same job is [ T = \frac{W}{r_A}. ]

2.2 Two workers working together

Assume worker (A) works at rate (r_A) and worker (B) at rate (r_B).
When both work together, the combined rate is [ r_{AB} = r_A + r_B. ] Thus the time to finish the job is [ T_{AB} = \frac{W}{r_A + r_B}. ] [ \boxed{\frac{1}{T_{AB}} = \frac{1}{T_A} + \frac{1}{T_B}} ] The reciprocal of time is linear in the reciprocal of individual times.

2.3 Many workers

For (n) workers, [ T = \frac{W}{\sum_{i=1}^n r_i} = \frac{W}{\sum_{i=1}^n \frac{1}{T_i}} ] where (T_i = W/r_i) is the time worker (i) would take alone.


3. Edge Cases & Common Pitfalls

Scenario What to Watch Out For Typical Mistake Correct Handling
Zero rate A worker who cannot work (e.g., due to injury) Counting them as “working” Exclude from the sum; set (r_i = 0).
Infinite time Work cannot be done (no one works) Forcing a division by zero Declare the job impossible.
Negative rate A worker undoes work (e.g., a mistake or sabotage). Treating as positive Allow negative terms in the sum; time may become negative, indicating the job will unfinish itself.
Partial work Workers don’t start at the same instant. Adding rates before aligning start times Use piecewise integration or add delayed work: (W = r_A t_A + r_B t_B + \dots).
Non‑constant rates Workers’ efficiency changes over time. Using a single rate Integrate: (W = \int_0^t r_i(\tau) d\tau).
Task switching Workers switch between tasks or take breaks. Assuming continuous work Model break periods with a piecewise function or separate integrals.

4. Advanced Theory

4.1 Continuous Time & Variable Rates

When a worker’s efficiency changes, we treat (r_i(t)) as a rate function.
The total work done by worker (i) over ([0,T]) is [ W_i = \int_0^T r_i(t), dt. ] If (r_i(t)) is linear, piecewise linear, or exponential, we can integrate analytically.
Example: a worker who gets tired, with rate (r(t) = r_0 - \alpha t).
Then [ W = \int_0^T (r_0 - \alpha t), dt = r_0 T - \frac{\alpha}{2}T^2. ]

4.2 Stochastic Work Rates

In real life, rates may be random due to variability.
We model (r_i) as a random variable and work as a random variable: [ W = \sum_{i=1}^n \int_0^T r_i(\tau), d\tau. ] We can compute expectations: [ \mathbb{E}[W] = \sum_{i=1}^n \int_0^T

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