Chandigarh Police Sub-Inspector (SI) /Quantitative Aptitude

Time & work

Commercial Maths · free study notes

Time & Work – Advanced Study Notes

Target audience: Chandigarh Police Sub‑Inspector (SI) exam candidates
Depth: MIT‑level, first‑principles, rigorous reasoning, edge cases, and a challenging problem

Tip: Keep the “work” symbol (W) universal. All rates, times, and efficiencies will be expressed in terms of (W), making it easy to compare units and track dimensions.


1. Overview

Concept Symbol Unit
Work performed (W) “Work units” (e.g., person‑days)
Rate of a worker (r) (W/\text{time})
Time taken (t) (\text{time})
Efficiency factor (e) dimensionless (ratio of actual to ideal work)

Fundamental Law of Work
[ \boxed{W = r \times t} ] This relationship holds regardless of the shape of the job, whether the worker is human, machine, or team.


2. First‑Principles Derivation

  1. Define a “unit of work”
    For any job, choose a reference unit (e.g., one wall painted, one kilometer paved).
    Let (W_{\text{ref}}) be the total amount of such units required.

  2. Rate as derivative of work w.r.t. time
    [ r = \frac{dW}{dt} ] If (W) is linear in time (constant rate), integrate: [ W(t) = r t + C ] At (t=0), (W=0), so (C=0). Hence (W = r t).

  3. Dimensional consistency
    ([W] = \frac{[W]}{[t]} \times [t]).
    The equation is dimensionally sound.


3. Work with Multiple Workers

3.1 Combined Rates

If workers A, B, C… work together:

[ r_{\text{total}} = r_A + r_B + r_C + \dots ]

Example

  • A: 3 W/day
  • B: 5 W/day
  • Combined: (8) W/day → 1 day to finish (8) W job.

3.2 Partitioning Work Between Workers

If a job requires (W) and two workers A and B finish it together in (t) days:

[ r_A + r_B = \frac{W}{t} ]

If we know the ratio (r_A : r_B = m : n):

[ r_A = \frac{m}{m+n}\frac{W}{t}, \qquad r_B = \frac{n}{m+n}\frac{W}{t} ]


4. Edge Cases & Common Pitfalls

Edge Case What Happens How to Handle
Zero work (W=0) Any worker can finish instantly Set (t=0) or treat as trivial
Zero rate (r=0) Work never progresses Infinite time, impossible job
Negative rate Indicates loss of work (e.g., sabotage) Treat as (r<0); time becomes negative → impossible
Partial work Some work already done Subtract completed work from (W)
Different units Minutes vs. hours Convert to common unit before applying formulas
Time-dependent rate Rate varies with fatigue Use integral (\int r(t) dt = W)
Simultaneous vs. sequential Order matters For sequential, add times; for simultaneous, use combined rate

Pitfall:

  • Mis‑reading “half” vs. “½.”
    “Half the work” means (0.5W), not (W/2) if (W) is already a fraction of a job.

5. Advanced Topics

5.1 Inverse Proportionality

If two workers A and B can finish a job in (t_A) and (t_B) days respectively, then:

[ r_A = \frac{W}{t_A}, \qquad r_B = \frac{W}{t_B} ]

When they work together:

[ t_{\text{AB}} = \frac{1}{\frac{1}{t_A} + \frac{1}{t_B}} ; \text{(harmonic mean)} ]

Example

  • A: 8 days, B: 12 days → Combined time (= \frac{1}{1/8+1/12} = 4.8) days.

5.2 Efficiency Factors

If a worker has efficiency (e) (0 < e ≤ 1), the effective rate becomes (e r).

Example:

  • Ideal rate (= 5) W/day; Efficiency (= 0.8) → Effective rate (= 4) W/day.

5.3 Work vs. Distance Analogy

Think of work like distance

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