Lakshadweep Patwari / Lekhpal /Quantitative Aptitude

Time & work

Commercial Maths · free study notes

Time & Work – Quick & Easy Study Notes

(For Lakshadweep Patwari / Lekhpal – Quantitative Aptitude)


1. What Does “Time & Work” Mean?

  • Work is the job that must be finished (e.g., painting a wall, filling a tank).
  • Time is how long it takes to finish that job.
  • Work Rate (how fast someone works) = amount of work done per unit of time.

Analogy:
Think of a bucket that needs to be filled with water.
• One person can fill it in 4 hours (they’re the “worker”).
• Two people together can fill it faster (their combined “work rate” is higher).


2. Basic Idea – Work = Rate × Time

Work (W) = Rate (R) × Time (T)
  • Rate (R) = units of work per hour.
  • Time (T) = hours spent working.
  • Work (W) = total units of job (usually set as 1 whole job).

3. Simple Steps to Solve a Problem

Step What to Do Example
1️⃣ Find each worker’s rate.
Rate = 1 / Time to finish alone.
A can finish in 5 hrs → Rate = 1/5 job per hr
2️⃣ Add rates if workers work together. A + B → (1/5) + (1/8)
3️⃣ Find combined rate. (1/5)+(1/8) = 13/40 job/hr
4️⃣ Use Work = Rate × Time to find needed time.
Time = Work / Rate.
Time = 1 / (13/40) = 40/13 ≈ 3.08 hrs
5️⃣ Round or convert to minutes if needed. 3 hrs + 0.08×60 ≈ 3 hrs 5 min

4. Tiny Example

Question:

  • A can fill a tank in 6 hrs.
  • B can fill it in 12 hrs.
  • How long will they take together?

Solution:

  1. A’s rate = 1/6 job/hr.
  2. B’s rate = 1/12 job/hr.
  3. Combined rate = 1/6 + 1/12 = 2/12 + 1/12 = 3/12 = 1/4 job/hr.
  4. Time = 1 job ÷ (1/4 job/hr) = 4 hrs.

Answer: 4 hours.


5. Common Variations

Variation How to Handle
One worker leaves early Subtract the time they worked from total time, then solve for the remaining worker.
Work is split between workers Use Work = Rate × Time for each part and add the times.
Work done after a break Treat break as “no work” (time does not contribute).
Different units (e.g., “days” instead of “hours”) Keep units consistent; convert if necessary.

6. Quick Practice Problems

  1. Simple:

    • A finishes a job in 8 hrs.
    • B finishes the same job in 12 hrs.
    • Find the time if they work together.
  2. One leaves early:

    • A can finish a task in 10 hrs.
    • B can finish it in 15 hrs.
    • They start together, but B leaves after 2 hrs.
    • How long does A finish the rest?
  3. Work split:

    • A works for 3 hrs, then B joins.
    • Together they finish the job in 5 hrs total.
    • If A alone would finish the job in 10 hrs, find B’s time to finish alone.

(Try solving before checking the answers in the next section.)


7. Answers to Practice Problems

  1. Time together

    • Rate A = 1/8, Rate B = 1/12.
    • Combined rate = 1/8 + 1/12 = 5/24.
    • Time = 1 ÷ (5/24) = 24/5 = 4.8 hrs (4 hrs 48 min).
  2. B leaves after 2 hrs

    • A’s rate = 1/10.
    • B’s rate = 1/15.
    • Work done in first 2 hrs by both = 2(1/10 + 1/15) = 2(5/50 + 3.33/50) ≈ 2(0.1 + 0.0667) = 0.3333.
    • Remaining work = 1 – 0.3333 = 0.6667.
    • A’s remaining time = 0.6667 ÷ (1/10) = 6.667 hrs (6 hrs 40 min).
  3. B’s time to finish alone

    • A’s rate = 1/10.
    • A works 3 hrs → work done = 3 × 1/10 = 0.3.
    • Remaining work = 0.7.
    • Total time together = 5 hrs, so together did 5 × (1/10 + 1/?) = 0.7.
    • Let B’s rate = 1/x.
    • (1/10 + 1/x) × 5 = 0.7 → (0.1 + 1/x) × 5 = 0.7 → 0.5 + 5/x = 0.7 → 5/x = 0.2 → x = 25.
    • B finishes alone in 25 hrs.

8. Quick Tips

  • Keep work = 1 job for simplicity.
  • Always convert times to the same unit (hrs or min).
  • Remember “Rate” is 1 ÷ Time.
  • Check your answer: if time seems too low or high, redo the rate calculation.

Final Thought

Think of “time & work” like mixing

Your note

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